Вот возможное решение:
import pandas as pd
import numpy as np
columns = ["evt", "pcle", "bin_0", "bin_1", "bin_2", "bin_3"]
data = [[1, "pi", 1, 0, 0, 0],
[1, "pi", 0, 0, 0, 0],
[1, "k", 0, 0, 0, 1],
[1, "pi", 0, 0, 1, 0],
[2, "pi", 0, 0, 1, 0],
[2, "k", 0, 1, 0, 0],
[3, "J", 0, 1, 0, 0],
[3, "pi", 0, 0, 0, 1],
[3, "pi", 1, 0, 0, 0],
[3, "k", 0, 1, 0, 0]]
df = pd.DataFrame(data=data, columns=columns)
# group your data by the columns you want
grouped = df.groupby(["evt", "pcle"])
# compute the aggregates for the bin_X
df_t = grouped.aggregate(np.sum)
# move pcle from index to column
df_t.reset_index(level=["pcle"], inplace=True)
# count occurrences of pcle
df_t["cant"] = grouped.size().values
# filter evt with .loc
df_t.loc[1]
Если вы хотите превратить его в словарь, вы можете выполнить:
d = {i:j.reset_index(drop=True) for i, j in df_t.groupby(df_t.index)}