Разница двух дат времени в SQL Server

Question

Есть ли способ определить разницу между двумя datetime на сервере sql?

Например, мои даты

1. 2010-01-22 15:29:55.090
2. 2010-01-22 15:30:09.153

Итак, результат должен быть 14.063 seconds.

Answer 1

Так что это не мой ответ, но я просто нашел его, когда искал в Интернете вопрос, подобный этому. Этот парень настроил процедуру для вычисления часов, минут и секунд. ссылка и код:

--Creating Function
If OBJECT_ID('UFN_HourMinuteSecond') Is Not Null
Drop Function dbo.UFN_HourMinuteSecond
Go
Exec(
'Create Function dbo.UFN_HourMinuteSecond
(
@StartDateTime DateTime,
@EndDateTime DateTime
) Returns Varchar(10) 
As
Begin

Declare @Seconds Int,
@Minute Int,
@Hour Int,
@Elapsed Varchar(10)

Select @Seconds = ABS(DateDiff(SECOND ,@StartDateTime,@EndDateTime))

If @Seconds >= 60 
Begin
select @Minute = @Seconds/60
select @Seconds = @Seconds%60

If @Minute >= 60
begin
select @hour = @Minute/60
select @Minute = @Minute%60
end

Else
Goto Final 
End

Final:
Select @Hour = Isnull(@Hour,0), @Minute = IsNull(@Minute,0), @Seconds =               IsNull(@Seconds,0)
select @Elapsed = Cast(@Hour as Varchar) + '':'' + Cast(@Minute as Varchar) + '':'' +     Cast(@Seconds as Varchar)

Return (@Elapsed)
End'
)

Answer 2

ПЕЧАТЬ DATEDIFF (второе, '2010-01-22 15: 29: 55.090', '2010-01-22 15: 30: 09.153')

Answer 3

Пожалуйста, отметьте ниже уловку, чтобы найти разницу между двумя датами

 DATEDIFF(DAY,ordr.DocDate,RDR1.U_ProgDate) datedifff

, где вы можете изменить в соответствии с вашими требованиями, как вы хотите разницу дней или месяцев или года или времени.

Answer 4

Sol-1:

select 
  StartTime
  , EndTime
  , CONVERT(NVARCHAR,(EndTime-StartTime), 108) as TimeDiff 
from 
  [YourTable]

Sol-2:

select 
  StartTime
  , EndTime
  , DATEDIFF(hh, StartTime, EndTime)
  , DATEDIFF(mi, StartTime, EndTime) % 60 
from 
  [YourTable]

Sol-3:

select 
  DATEPART(hour,[EndTime]-[StartTime])
  , DATEPART(minute,[EndTime]-[StartTime]) 
from 
  [YourTable]

Datepart работает лучше всего

Answer 5

CREATE FUNCTION getDateDiffHours (@fdate AS datetime, @ tdate как datetime) ВОЗВРАЩАЕТСЯ varchar (50) КАК НАЧАТЬ ОБЪЯВИТЬ @cnt int ОБЪЯВИТЬ @cntDate datetime ОБЪЯВИТЬ @dayDiff int ОБЪЯВИТЬ @dayDiffWk int ОБЪЯВИТЬ @hrsDiff decimal (18)

DECLARE @markerFDate datetime
DECLARE @markerTDate datetime

DECLARE @fTime int
DECLARE @tTime int 


DECLARE @nfTime varchar(8)
DECLARE @ntTime varchar(8)

DECLARE @nfdate datetime
DECLARE @ntdate datetime

-------------------------------------
--DECLARE @fdate datetime
--DECLARE @tdate datetime

--SET @fdate = '2005-04-18 00:00:00.000'
--SET @tdate = '2005-08-26 15:06:07.030'
-------------------------------------

DECLARE @tempdate datetime

--setting weekends
SET @fdate = dbo.getVDate(@fdate)
SET @tdate = dbo.getVDate(@tdate)
--RETURN @fdate 

SET @fTime = datepart(hh,@fdate)
SET @tTime = datepart(hh,@tdate)
--RETURN @fTime 
if datediff(hour,@fdate, @tdate) <= 9

        RETURN(convert(varchar(50),0) + ' Days ' + convert(varchar(50),datediff(hour,@fdate, @tdate)))  + ' Hours'
else
--setting working hours
SET @nfTime = dbo.getV00(convert(varchar(2),datepart(hh,@fdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,@fdate))) + ':'+  dbo.getV00(convert(varchar(2),datepart(ss,@fdate)))
SET @ntTime = dbo.getV00(convert(varchar(2),datepart(hh,@tdate))) + ':' +dbo.getV00(convert(varchar(2),datepart(mi,@tdate))) + ':'+  dbo.getV00(convert(varchar(2),datepart(ss,@tdate)))

IF @fTime > 17 
begin
    set @nfTime = '17:00:00'
end 
else
begin
    IF @fTime < 8 
        set @nfTime = '08:00:00'
end 

IF @tTime > 17 
begin
    set @ntTime = '17:00:00'
end 
else
begin
    IF @tTime < 8 
        set @ntTime = '08:00:00'
end 



-- used for working out whole days

SET @nfdate = dateadd(day,1,@fdate) 

SET @ntdate = @tdate
SET @nfdate = convert(varchar,datepart(yyyy,@nfdate)) + '-' + convert(varchar,datepart(mm,@nfdate)) + '-' + convert(varchar,datepart(dd,@nfdate))
SET @ntdate = convert(varchar,datepart(yyyy,@ntdate)) + '-' + convert(varchar,datepart(mm,@ntdate)) + '-' + convert(varchar,datepart(dd,@ntdate))
SET @cnt = 0
SET @dayDiff = 0 
SET @cntDate = @nfdate
SET @dayDiffWk = convert(decimal(18,2),@ntdate-@nfdate)

--select @nfdate,@ntdate

WHILE @cnt < @dayDiffWk
BEGIN   
    IF (NOT DATENAME(dw, @cntDate) = 'Saturday') AND (NOT DATENAME(dw, @cntDate) = 'Sunday')
    BEGIN 
        SET @dayDiff = @dayDiff + 1
    END 
    SET @cntDate = dateadd(day,1,@cntDate)
    SET @cnt = @cnt + 1
END 

--SET @dayDiff = convert(decimal(18,2),@ntdate-@nfdate) --datediff(day,@nfdate,@ntdate)
--SELECT @dayDiff

set @fdate = convert(varchar,datepart(yyyy,@fdate)) + '-' + convert(varchar,datepart(mm,@fdate)) + '-' + convert(varchar,datepart(dd,@fdate)) + ' ' + @nfTime
set @tdate = convert(varchar,datepart(yyyy,@tdate)) + '-' + convert(varchar,datepart(mm,@tdate)) + '-' + convert(varchar,datepart(dd,@tdate)) + ' ' + @ntTime

set @markerFDate = convert(varchar,datepart(yyyy,@fdate)) + '-' + convert(varchar,datepart(mm,@fdate)) + '-' + convert(varchar,datepart(dd,@fdate)) + ' ' + '17:00:00'
set @markerTDate = convert(varchar,datepart(yyyy,@tdate)) + '-' + convert(varchar,datepart(mm,@tdate)) + '-' + convert(varchar,datepart(dd,@tdate)) + ' ' + '08:00:00'

--select @fdate,@tdate
--select @markerFDate,@markerTDate

set @hrsDiff = convert(decimal(18,2),datediff(hh,@fdate,@markerFDate))

--select @hrsDiff
set @hrsDiff = @hrsDiff +  convert(int,datediff(hh,@markerTDate,@tdate))

--select @fdate,@tdate  

IF convert(varchar,datepart(yyyy,@fdate)) + '-' + convert(varchar,datepart(mm,@fdate)) + '-' + convert(varchar,datepart(dd,@fdate)) = convert(varchar,datepart(yyyy,@tdate)) + '-' + convert(varchar,datepart(mm,@tdate)) + '-' + convert(varchar,datepart(dd,@tdate))  
BEGIN
    --SET @hrsDiff = @hrsDiff - 9
    Set @hrsdiff = datediff(hour,@fdate,@tdate)
END 

--select FLOOR((@hrsDiff / 9))

IF (@hrsDiff / 9) > 0 
BEGIN
    SET @dayDiff = @dayDiff + FLOOR(@hrsDiff / 9)
    SET @hrsDiff = @hrsDiff - FLOOR(@hrsDiff / 9)*9
END 

--select convert(varchar(50),@dayDiff) + ' Days ' + convert(varchar(50),@hrsDiff)   + ' Hours'

RETURN(convert(varchar(50),@dayDiff) + ' Days ' + convert(varchar(50),@hrsDiff))    + ' Hours'

END

Answer 6

declare @dt1 datetime='2012/06/13 08:11:12', @dt2 datetime='2012/06/12 02:11:12'

select CAST((@dt2-@dt1) as time(0))

Answer 7

select
datediff(millisecond,'2010-01-22 15:29:55.090','2010-01-22 15:30:09.153') / 1000.0 as Secs

result:
Secs
14.063

Просто подумал, что упомяну это.

Answer 8

Проверьте DateDiff на Books Online.

Answer 9

для меня это работало отлично Преобразование (VARCHAR (8), DATEADD (ВТОРОЙ, DATEDIFF (ВТОРОЙ, LogInTime, LogOutTime), 0), 114) * * +1001

и вывод ЧЧ: ММ: СС, что точно показано в моем случае.