Как сделать сумму суммы в запросе MySQL

Question

SELECT a.id AS supplier, sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier

выход присутствует

supplier    total_qty
12046      475.00
12482      99.00

Требуется вывод

total_qty
574.00

здесь мне нужна сумма (total_qty) в этом запросе? как этого добиться

Answer 1

Просто изменить GROUP BY, добавив WITH ROLLUP:

SELECT a.id AS supplier, sum( processed_weight ) AS total_qty
FROM supplier_inward a
  INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier
  WITH ROLLUP

Выход:

supplier    total_qty
12046       475.00
12482        99.00
NULL        574.00

Answer 2

как насчет этого:

SELECT SUM(iQuery.total_qty) as iTotal
FROM
    (SELECT a.id AS supplier, sum( processed_weight ) AS total_qty
    FROM supplier_inward a
    INNER JOIN warehouseb ON a.id = b.supplier
    WHERE a.master_product_id = '38'
    GROUP BY b.supplier) as iQuery

Answer 3

1001 * попробовать *

SELECT sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'

РЕДАКТИРОВАТЬ 2 - ПОСЛЕ комментария от ОП изменение структуры результата:

Для дополнительного столбца попробуйте:

SELECT 
X.supplier,
X.total_qty,
(SELECT sum( processed_weight ) 
 FROM supplier_inward a
 INNER JOIN warehouseb ON a.id = b.supplier
 WHERE a.master_product_id = '38') AS totalq
FROM
(
SELECT 
a.id AS supplier, 
sum( processed_weight ) AS total_qty, 
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier) AS X

Для дополнительного ряда:

SELECT 
a.id AS supplier, 
sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38'
GROUP BY b.supplier
UNION ALL
SELECT null, X.total_qty
FROM
( 
SELECT sum( processed_weight ) AS total_qty
FROM supplier_inward a
INNER JOIN warehouseb ON a.id = b.supplier
WHERE a.master_product_id = '38' ) AS X

Answer 4

попробуйте без использования группы, поскольку вы хотите суммировать все