Вот более сложное решение, которое я только что написал, которое учитывает составные ординалы.Так что он работает от first до nine hundred and ninety ninth.Мне нужно было преобразовать названия улиц в числовые порядковые числа:
import re
from collections import OrderedDict
ONETHS = {
'first': '1ST', 'second': '2ND', 'third': '3RD', 'fourth': '4TH', 'fifth': '5TH', 'sixth': '6TH', 'seventh': '7TH',
'eighth': '8TH', 'ninth': '9TH'
}
TEENTHS = {
'tenth': '10TH', 'eleventh': '11TH', 'twelfth': '12TH', 'thirteenth': '13TH',
'fourteenth': '14TH', 'fifteenth': '15TH', 'sixteenth': '16TH', 'seventeenth': '17TH', 'eighteenth': '18TH',
'nineteenth': '19TH'
}
TENTHS = {
'twentieth': '20TH', 'thirtieth': '30TH', 'fortieth': '40TH', 'fiftieth': '50TH', 'sixtieth': '60TH',
'seventieth': '70TH', 'eightieth': '80TH', 'ninetieth': '90TH',
}
HUNDREDTH = {'hundredth': '100TH'} # HUNDREDTH not s
ONES = {'one': '1', 'two': '2', 'three': '3', 'four': '4', 'five': '5', 'six': '6', 'seven': '7', 'eight': '8',
'nine': '9'}
TENS = {'twenty': '20', 'thirty': '30', 'forty': '40', 'fifty': '50', 'sixty': '60', 'seventy': '70', 'eighty': '80',
'ninety': '90'}
HUNDRED = {'hundred': '100'}
# Used below for ALL_ORDINALS
ALL_THS = {}
ALL_THS.update(ONETHS)
ALL_THS.update(TEENTHS)
ALL_THS.update(TENTHS)
ALL_THS.update(HUNDREDTH)
ALL_ORDINALS = OrderedDict()
ALL_ORDINALS.update(ALL_THS)
ALL_ORDINALS.update(TENS)
ALL_ORDINALS.update(HUNDRED)
ALL_ORDINALS.update(ONES)
def split_ordinal_word(word):
ordinals = []
if not word:
return ordinals
for key, value in ALL_ORDINALS.items():
if word.startswith(key):
ordinals.append(key)
ordinals += split_ordinal_word(word[len(key):])
break
return ordinals
def get_ordinals(s):
ordinals, start, end = [], [], []
s = s.strip().replace('-', ' ').replace('and', '').lower()
s = re.sub(' +',' ', s) # Replace multiple spaces with a single space
s = s.split(' ')
for word in s:
found_ordinals = split_ordinal_word(word)
if found_ordinals:
ordinals += found_ordinals
else: # else if word, for covering blanks
if ordinals: # Already have some ordinals
end.append(word)
else:
start.append(word)
return start, ordinals, end
def detect_ordinal_pattern(ordinals):
ordinal_length = len(ordinals)
ordinal_string = '' # ' '.join(ordinals)
if ordinal_length == 1:
ordinal_string = ALL_ORDINALS[ordinals[0]]
elif ordinal_length == 2:
if ordinals[0] in ONES.keys() and ordinals[1] in HUNDREDTH.keys():
ordinal_string = ONES[ordinals[0]] + '00TH'
elif ordinals[0] in HUNDRED.keys() and ordinals[1] in ONETHS.keys():
ordinal_string = HUNDRED[ordinals[0]][:-1] + ONETHS[ordinals[1]]
elif ordinals[0] in TENS.keys() and ordinals[1] in ONETHS.keys():
ordinal_string = TENS[ordinals[0]][0] + ONETHS[ordinals[1]]
elif ordinal_length == 3:
if ordinals[0] in HUNDRED.keys() and ordinals[1] in TENS.keys() and ordinals[2] in ONETHS.keys():
ordinal_string = HUNDRED[ordinals[0]][0] + TENS[ordinals[1]][0] + ONETHS[ordinals[2]]
elif ordinals[0] in ONES.keys() and ordinals[1] in HUNDRED.keys() and ordinals[2] in ALL_THS.keys():
ordinal_string = ONES[ordinals[0]] + ALL_THS[ordinals[2]]
elif ordinal_length == 4:
if ordinals[0] in ONES.keys() and ordinals[1] in HUNDRED.keys() and ordinals[2] in TENS.keys() and \
ordinals[3] in ONETHS.keys():
ordinal_string = ONES[ordinals[0]] + TENS[ordinals[2]][0] + ONETHS[ordinals[3]]
return ordinal_string
А вот пример использования:
# s = '32 one hundred and forty-third st toronto, on'
#s = '32 forty-third st toronto, on'
#s = '32 one-hundredth st toronto, on'
#s = '32 hundred and third st toronto, on'
#s = '32 hundred and thirty first st toronto, on'
# s = '32 nine hundred and twenty third st toronto, on'
#s = '32 nine hundred and ninety ninth st toronto, on'
s = '32 sixty sixth toronto, on'
st, ords, en = get_ordinals(s)
print st, detect_ordinal_pattern(ords), en