Как читать объединенные ячейки в python, используя openpyxl?

Question

Я пытаюсь прочитать данные из файла excel, который имеет merged_cells_range ... но вывод не моя цель.Пожалуйста, помогите мне

import openpyxl
wb = openpyxl.load_workbook('book1.xlsx')
sheet = wb.get_sheet_by_name('info')
all_data=[]
print(sheet.merged_cells.ranges)
for row_index in range(1,sheet.max_row+1):
    row=[]
    for col_index in range(1,sheet.max_column+1):
        vals = sheet.cell(row_index,col_index).value
        if vals =='':
            for crange in sheet.merged_cells.ranges:
                rlo,rhi,clo,chi = crange
                if rlo<=row_index and row_index<rhi and clo<=col_index and col_index<chi:
                    vals = sheet.cell(rlo,clo).value
                    print(vals)
                    break
        row.append(vals)
    all_data.append(row)
print(all_data)
for row in all_data:
    sheet.append(row)
wb.save('bbbb.xlsx')

Я хотел получить вывод: [['06B', 'Daewoo BC 212', 80, 1373], ['06C', 'Daewoo BC 212', 80, 1020], ['06D', 'Transinco B60KL', 60, 1061], ['06D', 'Transinco B60KL', 60, 19], ['06E', 'Daewoo BC 212', 80, 1020], ['06E ',' Daewoo BC 212 ', 60, 1061], [' 06E ',' Daewoo BC 212 ', 60, 19]], но результаты таковы:

[[' 06B ',' Daewoo BC 212', 80, 1373], [' 06C ',' Daewoo BC 212 ', 80, 1020], [' 06D ',' Transinco B60KL ', 60, 1061], [Нет, нет, 60, 19], ['06E ',' Daewoo BC 212 ', 80, 1020], [Нет, Нет, 60, 1061], [Нет, Нет, 60, 19]]

мой ввод желаемый вывод

Answer 1

Я исправляю свой код, и он работает.

import openpyxl
from openpyxl.utils import range_boundaries
wb = openpyxl.load_workbook('book1.xlsx')
sheet = wb.get_sheet_by_name('info')
all_data=[]
for row_index in range(1,sheet.max_row+1):
    row=[]
    for col_index in range(1,sheet.max_column+1):
        vals = sheet.cell(row_index,col_index).value
        if vals == None:
            for crange in sheet.merged_cells:
                clo,rlo,chi,rhi = crange.bounds
                top_value = sheet.cell(rlo,clo).value
                if rlo<=row_index and row_index<=rhi and clo<=col_index and col_index<=chi:
                vals = top_value
                    print(vals)
                    break
    row.append(vals)
all_data.append(row)
print(all_data)
for row in all_data:
    sheet.append(row)
wb.save('bbbb.xlsx')

Answer 2

Вот, пожалуйста:

= ^ .. ^ =

import openpyxl
from openpyxl import Workbook

# load data
raw_data = openpyxl.load_workbook('data.xlsx')
select_sheet = raw_data['Sheet1']


# collect data from rows
valid_row = []
data = []
for row in select_sheet.iter_rows(max_row=select_sheet.max_row, max_col=select_sheet.max_column):
    # get cell values
    row_data = [cell.value for cell in row]

    # handle merged cells
    new_row_data = [0]*select_sheet.max_column
    if None in row_data:
        new_row_data[0] = valid_row[0]
        new_row_data[1] = valid_row[1]
        new_row_data[2] = row_data[2]
        new_row_data[3] = row_data[3]
        data.append(new_row_data)
    else:
        data.append(row_data)
    # storage valid row
    if None not in row_data:
        valid_row = row_data


# save data
book = Workbook()
new_sheet = book.active

for row in data:
    new_sheet.append(row)

book.save('new_data.xlsx')

Введите:

     0    1    2    3
0    B   212   80  1.2
1    C   212   80  1.3
2    D   B60   60  1.4
3  None  None  60  1.5
4    E   212   80  1.6
5  None  None  60  1.7
6  None  None  60  1.8

Выход:

   0    1   2    3
0  B  212  80  1.2
1  C  212  80  1.3
2  D  B60  60  1.4
3  D  B60  60  1.5
4  E  212  80  1.6
5  E  212  60  1.7
6  E  212  60  1.8