Почему этот подзапрос hiveql не работает?

Question

select (
    SELECT SUM(countNumber) from(
            SELECT FROM_UNIXTIME(unix_timestamp(AddTime),'yyyy-MM-dd') AS dateTime,
                   COUNT(productID) AS countNumber
              FROM product
             GROUP BY FROM_UNIXTIME(unix_timestamp(AddTime),'yyyy-MM-dd')
           ) as bb
     where aa.dateTime >= bb.dateTime
   ) as totalCount,
   aa.countNumber,
   aa.dateTimefrom (
    SELECT FROM_UNIXTIME(unix_timestamp(AddTime),'yyyy-MM-dd')AS dateTime,
           COUNT(productID) AS countNumber
      FROM product
     GROUP BY FROM_UNIXTIME(unix_timestamp(AddTime),'yyyy-MM-dd')
   ) aa order by dateTime desc limit 10000;

Я не хочу запрашивать ежедневное суммарное количество. Почему этот HQL не работает? Подсказка движка Hive:

FAILED: ParseException line 2:8 cannot recognize input near 'SELECT' 'SUM' '(' in expression specification

Answer 1

Подзапросы в виде столбцов не разрешены в Hive. Чтобы получить накопленное количество, используйте оконную функцию sum.

SELECT dateTime,countNumber,SUM(countNumber) OVER(order by dateTime) as cumsum
FROM (SELECT FROM_UNIXTIME(unix_timestamp(AddTime),'yyyy-MM-dd') AS dateTime,
      COUNT(productID) AS countNumber
      FROM product
      GROUP BY FROM_UNIXTIME(unix_timestamp(AddTime),'yyyy-MM-dd')
     ) t