Использование Журнала посещаемости и Таблицы дней ВЫКЛ. Как показать подарок, отсутствие и выходной день?

Question

Я получаю этот файл из журнала отпечатков пальцев с устройства:

Id User_id      CheckTime
--------------------------
1   152      2018-07-17 09:38:03
2   184      2018-07-17 16:56:43
3   152      2018-07-17 16:57:18
4   165      2018-07-17 16:57:43
5   70       2018-07-17 16:57:59
6   134      2018-07-17 16:58:28
7   276      2018-07-17 16:59:04
8   278      2018-07-17 16:59:05
9   271      2018-07-17 16:59:10
10  268      2018-07-17 16:59:13
11  284      2018-07-17 16:59:16
12  364      2018-07-17 16:59:35
13  19       2018-07-17 16:59:38
14  381      2018-07-17 17:01:12
15  73       2018-07-17 17:12:31
16  126      2018-07-17 17:12:36
17  382      2018-07-17 17:13:50
18  53       2018-07-18 06:34:13
19  284      2018-07-18 08:05:17

Как сделать запрос в запросе Postgres для извлечения данных, которые выглядят так:

User_id  Check_Date   DAY       TimeIN    TimeOUT   Hours   status
-----------------------------------------------------------------
152      2018-07-17   Tuesday    09:38:03 16:56:43  7.8     present
152      2018-07-18   Wednesday                              Absent

Использование этого запроса для получения результата

with from_thru as (
  select
    min (checktime)::date as from_date, 
    max (checktime)::date as thru_date
  from attendance_FHLHR
),
users as (
  select distinct userid, name from attendance_FHLHR
)
select
  gs.date::date, u.userid, u.name, to_char(gs.date::date, 'day') days,
  min (a.checktime) as TimeIn,
  max (a.checktime) as TimeOut,
uso.off_days as offf,
  extract (epoch from max (a.checktime) - min (a.checktime))/3600 as Hours,
  case
    when min (a.checktime) is null then 'Absent'
    when count (1) = 1 then 'Half Day' 
    else 'Present'
  end as status
from
  from_thru
  cross join generate_series (from_date, thru_date, interval '1 day') gs (date)
  cross join users u
  left join attendance_FHLHR a on
    a.checktime::date = gs.date and
    a.userid = u.userid
   left join users_staffuser us on a.emp_id::varchar = us.emp_id 
   left join users_staffuseroffdays uso on uso.staff_user_id = us.id
and us.emp_id is not null
group by
  gs.date, u.userid, u.name, uso.off_days
order by u.name ASC

Теперь у меня есть еще одна таблица, где у меня есть магазин выходных дней, например

.

name   userid   days
---------------------------
adnan   152     monday
kasih   182     tuesday

Как добавить в статусную колонку выходной день пользователя. Идентификатор пользователя не пробивает и проверяет данные, если у него выходной?

User_id  Check_Date   DAY       TimeIN    TimeOUT   Hours   status
-----------------------------------------------------------------
152      2018-07-17   Tuesday    09:38:03 16:56:43  7.8     present
152      2018-07-18   Wednesday                             OFF DAY
152      2018-07-19   thursday                              Absent

Answer 1

@ S-MAN, я решаю это. Yahoo

with from_thru as (
                      select
                        min (checktime)::date as from_date, 
                        max (checktime)::date as thru_date
                      from attendance_FHLHR
                    ),
                    users as (
                      select distinct userid, name, emp_id from attendance_FHLHR
                    )
                    select
                      gs.date::date, u.userid, u.name, to_char(gs.date::date, 'day') days,
                      min (a.checktime) as TimeIn,
                      max (a.checktime) as TimeOut,
                      extract (epoch from max (a.checktime) - min (a.checktime))/3600 as Hours,
                      case
                    when uso.off_days = 'monday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'tuesday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'wednesday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'wednesday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'thursday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'friday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'saturday' and min (a.checktime) is null  then 'Off Day'
                    when uso.off_days = 'sunday' and min (a.checktime) is null  then 'Off Day'
                        when   max(a.checktime) is null  then 'ABsent'
                        when count (1) = 1 then 'Half Day' 
                        else 'Present'
                      end as status
                    from
                      from_thru
                      cross join generate_series (from_date, thru_date, interval '1 day') gs (date)
                      cross join users u
                      left join attendance_FHLHR a on
                        a.checktime::date = gs.date and
                        a.userid = u.userid
                       left join users_staffuser us on u.emp_id::varchar = us.emp_id 
                       left join users_staffuseroffdays uso on uso.staff_user_id = us.id
                      -- and uso.off_days = to_char(gs.date::date, 'day')
                    and us.emp_id is not null
                    and uso.off_days = trim(to_char(gs.date::date, 'day'))
                    group by
                      gs.date, u.userid, u.name, uso.off_days
                    order by u.name ASC """)