Просто используйте псевдоним в предложении SELECT
:
SELECT COUNT(DISTINCT SubCategoryName) as SubCategoryNameCount, CategoryName
FROM v_EnterpriseStructure
GROUP BY CategoryName
ORDER BY COUNT(SubCategoryName);
или
SELECT SubCategoryNameCount = COUNT(DISTINCT SubCategoryName) , CategoryName
FROM v_EnterpriseStructure
GROUP BY CategoryName
ORDER BY COUNT(SubCategoryName);
или
SELECT COUNT(DISTINCT SubCategoryName) SubCategoryNameCount, CategoryName
FROM v_EnterpriseStructure
GROUP BY CategoryName
ORDER BY COUNT(SubCategoryName);
или
SELECT COUNT(DISTINCT SubCategoryName) 'SubCategoryNameCount', CategoryName
FROM v_EnterpriseStructure
GROUP BY CategoryName
ORDER BY COUNT(SubCategoryName);
или
SELECT COUNT(DISTINCT SubCategoryName) [SubCategoryNameCount], CategoryName
FROM v_EnterpriseStructure
GROUP BY CategoryName
ORDER BY COUNT(SubCategoryName);
Вывод всех вышеперечисленных запросов: