Java 8, получите Сортированную Карту Карт, используя два поля - PullRequest
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Java 8, получите Сортированную Карту Карт, используя два поля

0 голосов
/ 09 января 2019

Я хочу получить отсортированную карту, используя два поля (штат и муниципалитет) из несортированного списка.

Вот мои занятия 

class StateMunicipality {

  private StateMunicipalityId id;
  private String nameState;
  private String nameMunicipality;

  public StateMunicipality(StateMunicipalityId id, String nameState, String nameMunicipality) {
    this.id = id;
    this.nameState = nameState;
    this.nameMunicipality = nameMunicipality;
  }

  public StateMunicipalityId getId() {
    return id;
  }

  public void setId(StateMunicipalityId id) {
    this.id = id;
  }

  public String getNameState() {
    return nameState;
  }

  public void setNameState(String nameState) {
    this.nameState = nameState;
  }

  public String getNameMunicipality() {
    return nameMunicipality;
  }

  public void setNameMunicipality(String nameMunicipality) {
    this.nameMunicipality = nameMunicipality;
  }

  @Override
  public String toString() {
    return id + ", nameState=" + nameState + ", nameMunicipality=" + nameMunicipality;
  }

}

Идентификатор 

class StateMunicipalityId {

  private Long codeState;
  private Long codeMunicipality;

  public StateMunicipalityId(Long codeState, Long codeMunicipality) {
    this.codeState = codeState;
    this.codeMunicipality = codeMunicipality;
  }

  public Long getCodeState() {
    return codeState;
  }

  public void setCodeState(Long codeState) {
    this.codeState = codeState;
  }

  public Long getCodeMunicipality() {
    return codeMunicipality;
  }

  public void setCodeMunicipality(Long codeMunicipality) {
    this.codeMunicipality = codeMunicipality;
  }

  @Override
  public String toString() {
    return "codeState=" + codeState + ", codeMunicipality=" + codeMunicipality;
  }

}

Теперь я заполняю список 

System.out.println("Example unsorted List");
List<StateMunicipality> statmuns = new ArrayList<>();
statmuns.add(new StateMunicipality(new StateMunicipalityId(1L, 1L), "Atlántico", "Barranquilla"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(3L, 3L), "Antioquia", "Envigado"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(2L, 3L), "Valle", "Yumbo"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(3L, 2L), "Antioquia", "Itagüí"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(2L, 1L), "Valle", "Cali"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(3L, 1L), "Antioquia", "Medellín"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(1L, 2L), "Atlántico", "Soledad"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(1L, 3L), "Atlántico", "Puerto Colombia"));
statmuns.add(new StateMunicipality(new StateMunicipalityId(2L, 2L), "Valle", "Palmira"));

statmuns.stream().forEach(System.out::println);

Вывод, как был вставлен! 

Example unsorted List
codeState=1, codeMunicipality=1, nameState=Atlántico, nameMunicipality=Barranquilla
codeState=3, codeMunicipality=3, nameState=Antioquia, nameMunicipality=Envigado
codeState=2, codeMunicipality=3, nameState=Valle, nameMunicipality=Yumbo
codeState=3, codeMunicipality=2, nameState=Antioquia, nameMunicipality=Itagüí
codeState=2, codeMunicipality=1, nameState=Valle, nameMunicipality=Cali
codeState=3, codeMunicipality=1, nameState=Antioquia, nameMunicipality=Medellín
codeState=1, codeMunicipality=2, nameState=Atlántico, nameMunicipality=Soledad
codeState=1, codeMunicipality=3, nameState=Atlántico, nameMunicipality=Puerto Colombia
codeState=2, codeMunicipality=2, nameState=Valle, nameMunicipality=Palmira

Я ХОЧУ ПОЛУЧИТЬ (во вложенных отсортированных картах) в соответствии с этим порядком, сначала на nameState, затем nameMunicipality. 

codeState=3, codeMunicipality=3, nameState=Antioquia, nameMunicipality=Envigado
codeState=3, codeMunicipality=2, nameState=Antioquia, nameMunicipality=Itagüí
codeState=3, codeMunicipality=1, nameState=Antioquia, nameMunicipality=Medellín
codeState=1, codeMunicipality=1, nameState=Atlántico, nameMunicipality=Barranquilla
codeState=1, codeMunicipality=3, nameState=Atlántico, nameMunicipality=Puerto Colombia
codeState=1, codeMunicipality=2, nameState=Atlántico, nameMunicipality=Soledad
codeState=2, codeMunicipality=1, nameState=Valle, nameMunicipality=Cali
codeState=2, codeMunicipality=2, nameState=Valle, nameMunicipality=Palmira
codeState=2, codeMunicipality=3, nameState=Valle, nameMunicipality=Yumbo

Потом я генерировал свой EDITED код, НО я что-то упустил !! ... 

Map<Long, Map<Long, StateMunicipality>> sortedMapOfMaps = statmuns
        .stream().sorted(
                Comparator.comparing(StateMunicipality::getNameState).thenComparing(
                        Comparator.comparing(StateMunicipality::getNameMunicipality))
        ).collect(Collectors.groupingBy(
                statmuni -> statmuni.getId().getCodeState(),
                Collectors.toMap(
                        statmuni -> statmuni.getId().getCodeMunicipality(),
                        Function.identity(),
                        (e1, e2) -> e1, LinkedHashMap::new)
        ));

System.out.println("sortedMapOfMaps");
sortedMapOfMaps.entrySet().stream().forEach(
        set -> {
          //System.out.println(set.getKey() + " = " + set.getValue());
          set.getValue().forEach((key, val) -> {
            System.out.println(key + " = " + val.toString());
          });
        }
);

Я довольно близко! 

sortedMapOfMaps
1 = codeState=1, codeMunicipality=1, nameState=Atlántico, nameMunicipality=Barranquilla
3 = codeState=1, codeMunicipality=3, nameState=Atlántico, nameMunicipality=Puerto Colombia
2 = codeState=1, codeMunicipality=2, nameState=Atlántico, nameMunicipality=Soledad
1 = codeState=2, codeMunicipality=1, nameState=Valle, nameMunicipality=Cali
2 = codeState=2, codeMunicipality=2, nameState=Valle, nameMunicipality=Palmira
3 = codeState=2, codeMunicipality=3, nameState=Valle, nameMunicipality=Yumbo
3 = codeState=3, codeMunicipality=3, nameState=Antioquia, nameMunicipality=Envigado
2 = codeState=3, codeMunicipality=2, nameState=Antioquia, nameMunicipality=Itagüí
1 = codeState=3, codeMunicipality=1, nameState=Antioquia, nameMunicipality=Medellín

Мой код для SortedState. 

System.out.println("sortedMapState");
Map<Long, StateMunicipality> sortedMapState = statmuns.stream().sorted(
        Comparator.comparing(StateMunicipality::getNameState)
).collect(
        Collectors.toMap(stateMunicipality -> stateMunicipality.getId().getCodeState(),
                Function.identity(),
                (e1, e2) -> e1, LinkedHashMap::new)
);

sortedMapState.forEach((key, val) -> {
  System.out.println(key + " = " + val.getNameState());
});

У меня заказанная карта states

sortedMapState
3 = Antioquia
1 = Atlántico
2 = Valle

Какая часть мне не хватает?

...