База данных Laravel raw concat заменяет

Question

У меня проблема, ниже моего кода

$data = client_conf::select('cont_id','default_cont_id')->where('client_id',$client_id)->first();
$cont_id = explode(',', $data->cont_id);
$res_ = "'".implode("','", $cont_id)."'";

$custom2 = DB::table('client_conf as a')->where('client_id',$client_id)
    ->select(DB::raw("
        a.cont_id as id_list,
        a.default_cont_id id_default,
        (SELECT bank_fee_trans_inter FROM payout_cont as t WHERE t.cont_id=a.default_cont_id) as fee_trans_inter,
        (SELECT bank_fee_skn FROM payout_cont as t WHERE t.cont_id=a.default_cont_id) as fee_skn,
        (SELECT bank_fee_skn FROM payout_cont as t WHERE t.cont_id=a.default_cont_id) as fee_rtgs,
        (SELECT bank_fee_trans FROM payout_cont as t WHERE t.cont_id in ($res_) and t.bank_cd='$bank_cd') as fee_trans_same,
        (SELECT cont_id FROM payout_cont as t WHERE t.cont_id in ($res_) and t.bank_cd='$bank_cd') as id_trans
    "))
    ->first();

результат $ cont_id = AAA, BBB

Кто-нибудь может помочь упростить запрос? так что я могу сделать один раз запросы, не нужно делать дважды. (сначала запрашивает cont_id, затем я сначала взрываю его, затем выполняю второй).

проблема в $ res_

Я уже пытаюсь использовать concat и replace,

пример попытки: concat('\'',replace(a.cont_id,',',"','"),'\''). но получить результат id_trans = null.

Если кто-то может помочь решить эту проблему, я очень благодарен.

последний ->first() изменить на ->tosql()

SELECT a.cont_id AS id_list, a.default_cont_id id_default, 
       (SELECT bank_fee_trans_inter 
        FROM   payout_cont AS t 
        WHERE  t.cont_id = a.default_cont_id) AS fee_trans_inter, 
       (SELECT bank_fee_skn 
        FROM   payout_cont AS t 
        WHERE  t.cont_id = a.default_cont_id) AS fee_skn, 
       (SELECT bank_fee_skn 
        FROM   payout_cont AS t 
        WHERE  t.cont_id = a.default_cont_id) AS fee_rtgs, 
       (SELECT bank_fee_trans 
        FROM   payout_cont AS t 
        WHERE  t.cont_id IN ( 'AAAA', 'BBB' ) 
               AND t.bank_cd = 'CENA')        AS fee_trans_same, 
       (SELECT cont_id 
        FROM   payout_cont AS t 
        WHERE  t.cont_id IN ( 'AAAA', 'BBB' ) 
               AND t.bank_cd = 'CENA')        AS id_trans 
FROM   `client_conf` AS `a` 
WHERE  `client_id` = ? 

Я уже нахожу решение, используя find_in_set. ниже моего кода обновления

$custom2 = DB::table('client_conf as a')->where('client_id',$client_id)
            ->select(DB::raw("
                a.cont_id as id_list,
                a.default_cont_id id_default,
                (SELECT bank_fee_trans_inter FROM payout_cont as t WHERE t.cont_id=a.default_cont_id) as fee_trans_inter,
                (SELECT bank_fee_skn FROM payout_cont as t WHERE t.cont_id=a.default_cont_id) as fee_skn,
                (SELECT bank_fee_rtgs FROM payout_cont as t WHERE t.cont_id=a.default_cont_id) as fee_rtgs,
                (SELECT bank_fee_trans FROM payout_cont t,client_conf j WHERE FIND_IN_SET(t.cont_id,id_list) <> 0 and t.bank_cd='$bank_cd' group by t.bank_fee_trans) as fee_trans_same,
                (SELECT t.cont_id FROM payout_cont t,client_conf j WHERE FIND_IN_SET(t.cont_id,id_list) <> 0 and t.bank_cd='$bank_cd' group by t.cont_id) as id_trans
            "))
            ->first();