Я могу подключиться к RDS, но когда я пытаюсь создать таблицу с помощью следующего сценария, я получаю сообщение об ошибке.
<?php
define('DB_SERVER', 'rdsdari.MYRDSNAME.rds.amazonaws.com');
define('DB_USERNAME', 'Rds1');
define('DB_PASSWORD', 'Rds1');
define('DB_DATABASE', 'Rds1');
/* Connect to MySQL and select the database. */
$connection = mysqli_connect(DB_SERVER, DB_USERNAME, DB_PASSWORD);
if (mysqli_connect_errno()) echo "Failed to connect to MySQL: " . mysqli_connect_error();
$database = mysqli_select_db($connection, DB_DATABASE);
/* Ensure that the Employees table exists. */
VerifyEmployeesTable($connection, DB_DATABASE);
/* If input fields are populated, add a row to the Employees table. */
$employee_name = htmlentities($_POST['Name']);
$employee_address = htmlentities($_POST['Address']);
if (strlen($employee_name) || strlen($employee_address)) {
AddEmployee($connection, $employee_name, $employee_address);
}
?>
<!-- Input form -->
<form action="<?PHP echo $_SERVER['SCRIPT_NAME'] ?>" method="POST">
<table border="0">
<tr>
<td>Name</td>
<td>Address</td>
</tr>
<tr>
<td>
<input type="text" name="Name" maxlength="45" size="30" />
</td>
<td>
<input type="text" name="Address" maxlength="90" size="60" />
</td>
<td>
<input type="submit" value="Add Data" />
</td>
</tr>
</table>
</form>
<!-- Display table data. -->
<table border="1" cellpadding="2" cellspacing="2">
<tr>
<td>ID</td>
<td>Name</td>
<td>Address</td>
</tr>
<?php
$result = mysqli_query($connection, "SELECT * FROM Employees");
6,34 Top
}
?>
</table>
<!-- Clean up. -->
<?php
mysqli_free_result($result);
mysqli_close($connection);
?>
</body>
</html>
<?php
/* Add an employee to the table. */
function AddEmployee($connection, $name, $address) {
$n = mysqli_real_escape_string($connection, $name);
$a = mysqli_real_escape_string($connection, $address);
$query = "INSERT INTO `Employees` (`Name`, `Address`) VALUES ('$n', '$a');";
if(!mysqli_query($connection, $query)) echo("<p>Error adding employee data.</p>");
}
/* Check whether the table exists and, if not, create it. */
function VerifyEmployeesTable($connection, $dbName) {
if(!TableExists("Employees", $connection, $dbName))
{
$query = "CREATE TABLE `Employees` (
`ID` int(11) NOT NULL AUTO_INCREMENT,
`Name` varchar(45) DEFAULT NULL,
`Address` varchar(90) DEFAULT NULL,
PRIMARY KEY (`ID`),
UNIQUE KEY `ID_UNIQUE` (`ID`)
) ENGINE=InnoDB AUTO_INCREMENT=1 DEFAULT CHARSET=latin1";
if(!mysqli_query($connection, $query)) echo("<p>Error creating table.</p>");
}
}
/* Check for the existence of a table. */
function TableExists($tableName, $connection, $dbName) {
$t = mysqli_real_escape_string($connection, $tableName);
$d = mysqli_real_escape_string($connection, $dbName);
$checktable = mysqli_query($connection,
"SELECT TABLE_NAME FROM information_schema.TABLES WHERE TABLE_NAME = '$t' AND TABLE_SCHEMA = '$d'");
if(mysqli_num_rows($checktable) > 0) return true;
return false;
}
?>
и теперь я получаю
Ошибка создания таблицы.
Ошибка добавления данных о сотруднике.