match
и %in%
делают работу. Попробуйте это:
## example 1
df1 <- t(data.frame(seq(1,6,by=1),seq(6,1,by=-1)))
colnames(df1) <- c("ZZZ","YYY","CCC","DDD","XXX","KKK")
rownames(df1) <- c("a","b")
Vector1<-c("AAA", "BBB", "CCC", "DDD", "EEE", "FFF")
Vector2<-c("a", "b", "e", "f", "k", "l")
df2<-data.frame(cbind(Vector1, Vector2))
target <- match(colnames(df1), df2$Vector1, nomatch = 0)
colnames(df1)[colnames(df1) %in% df2$Vector1] <- as.character(df2$Vector2[target])
df1 # output
ZZZ YYY e f XXX KKK
a 1 2 3 4 5 6
b 6 5 4 3 2 1
#example 2
df1 <- t(data.frame(seq(1,6,by=1),seq(6,1,by=-1)))
colnames(df1) <- c("ZZZ","YYY","CCC","DDD","XXX","KKK")
rownames(df1) <- c("a","b")
Vector1<-c("KKK", "BBB", "DDD", "XXX", "EEE", "FFF")
Vector2<-c("a", "b", "e", "f", "k", "l")
df2<-data.frame(cbind(Vector1, Vector2))
target <- match(colnames(df1), df2$Vector1, nomatch = 0)
colnames(df1)[colnames(df1) %in% df2$Vector1] <- as.character(df2$Vector2[target])
df1 # output
ZZZ YYY CCC e f a
a 1 2 3 4 5 6
b 6 5 4 3 2 1