MYSQL - рассчитать пропорцию количества на ID

Question

Вот мой стол. Тип 0 для dislike, тип 1 для like.

id | userid | postid | type
1  |   465  |  20    |  0
2  |   465  |  21    |  1
3  |   466  |  20    |  1
4  |   466  |  21    |  0
5  |   467  |  20    |  1
6  |   467  |  21    |  0

Теперь мои запросы

$sql = $bdd->query('SELECT COUNT(id) AS cntLikes,  postid, type FROM like_unlike WHERE type = 1 GROUP BY postid, type');
$sql = $bdd->query('SELECT COUNT(id) AS cntUnlikes,  postid, type FROM like_unlike WHERE type = 0 GROUP BY postid, type');

Это показывает мне:

postid(20) -> 1 like 
postid(21) -> 2 like1

postid(20) -> 2 dislikes
postid(21) -> 1 dislike

Я хочу рассчитать% like и отобразить его для каждого postid.

$p = ($total_unlikes / ($total_unlikes+$total_likes)) * 100;

Я пробовал

$sql = $bdd->query("SELECT postid, COUNT(CASE type WHEN '1' THEN 1 END) AS cntLikes, COUNT(CASE type WHEN '0' THEN 1 END) AS cntunlikes from like_unlike GROUP BY postid, type");
    while ($donnees2 = $sql->fetch())  {
    $total_likes = $donnees2['cntLikes'];
    $total_unlikes = $donnees2['cntunlikes'];
    $ratio = ($total_unlikes / ($total_unlikes+$total_likes)) * 100;
    echo $donnees2['postid'],'  nb likes',$total_likes,' nb dislikes',$total_unlikes,'   percent',$p,'<br />';}

Но это показывает мне

postid(20)  -> nb likes 1 -> nb dislikes 0 -> percent 100
postid(20)  -> nb likes 0 -> nb dislikes 2 -> percent ->100
postid(21)  -> nb likes 2 -> nb dislikes 0 -> percent -> 100
postid(21)  -> nb likes 0 -> nb dislikes -> 1  percent ->100

Вот конечный результат, который я хочу:

postid(20)  -> nb likes 1 -> nb dislikes 2 -> percent 33
postid(21)  -> nb likes 2 -> nb dislikes 1 -> percent ->66

Answer 1

Удалите type из GROUP BY, чтобы вы не получали одну группу (и одну строку) для каждого типа, а одну для обоих.