применение построчной функции во фрейме данных со значениями другого фрейма данных

Question

У меня есть два фрейма данных:

df1

df1 = pd.DataFrame({ 'group' : ["A","A","A","B","B","B"],
   'par' : [5,5,15,10,2,11],
   'val' :[50,10,180,10,10,660],
   'set_0' :["Country","Country","Country","Country","Country","Country"],
   'set_1' :["size1","size1","size2","size3","size4","size3"],
   'set_2' :["size12","size12","size12","size9","size13","size13"],
   'set_3' :["size14","size14","size15","NO","NO","NO"],
   'set_4' :["NO","NO","NO","size25","size25","size27"],
   'set_5' :["NO","NO","NO","NO","NO","NO"]
                     })

df2

df2 = pd.DataFrame({ 'group' : ["A","A","A","A","A","A","B","B","B","B","B","B","B"],
   'set' : ["Country","size1","size2","size12","size14","size15","Country","size3","size4","size9","size13","size25","size27"],
                     })

Для каждой строки (группа Xустановить комбинацию) из df2, я хочу применить функцию для расчета (сумма "val" / сумма "par").

Я пытался использовать что-то с функцией apply, но я не мог понять, так как я довольно новичок в python.Может ли кто-нибудь помочь с решением проблемы?

Ниже приведен ожидаемый результат:

Поскольку загрузка изображений не удается, я такжеразделение ниже кода, чтобы получить результат самым уродливым и неэффективным способом жесткого кодирования:

a1=df1[(df1["group"]==df2.iloc[0,0])&(df1["set_0"]==df2.iloc[0,1])].sum()["val"]
a2=df1[(df1["group"]==df2.iloc[0,0])&(df1["set_0"]==df2.iloc[0,1])].sum()["par"]
b1=df1[(df1["group"]==df2.iloc[1,0])&(df1["set_1"]==df2.iloc[1,1])].sum()["val"]
b2=df1[(df1["group"]==df2.iloc[1,0])&(df1["set_1"]==df2.iloc[1,1])].sum()["par"]
c1=df1[(df1["group"]==df2.iloc[2,0])&(df1["set_1"]==df2.iloc[2,1])].sum()["val"]
c2=df1[(df1["group"]==df2.iloc[2,0])&(df1["set_1"]==df2.iloc[2,1])].sum()["par"]
d1=df1[(df1["group"]==df2.iloc[3,0])&(df1["set_2"]==df2.iloc[3,1])].sum()["val"]
d2=df1[(df1["group"]==df2.iloc[3,0])&(df1["set_2"]==df2.iloc[3,1])].sum()["par"]
e1=df1[(df1["group"]==df2.iloc[4,0])&(df1["set_3"]==df2.iloc[4,1])].sum()["val"]
e2=df1[(df1["group"]==df2.iloc[4,0])&(df1["set_3"]==df2.iloc[4,1])].sum()["par"]
f1=df1[(df1["group"]==df2.iloc[5,0])&(df1["set_3"]==df2.iloc[5,1])].sum()["val"]
f2=df1[(df1["group"]==df2.iloc[5,0])&(df1["set_3"]==df2.iloc[5,1])].sum()["par"]
g1=df1[(df1["group"]==df2.iloc[6,0])&(df1["set_0"]==df2.iloc[6,1])].sum()["val"]
g2=df1[(df1["group"]==df2.iloc[6,0])&(df1["set_0"]==df2.iloc[6,1])].sum()["par"]
h1=df1[(df1["group"]==df2.iloc[7,0])&(df1["set_1"]==df2.iloc[7,1])].sum()["val"]
h2=df1[(df1["group"]==df2.iloc[7,0])&(df1["set_1"]==df2.iloc[7,1])].sum()["par"]
j1=df1[(df1["group"]==df2.iloc[8,0])&(df1["set_1"]==df2.iloc[8,1])].sum()["val"]
j2=df1[(df1["group"]==df2.iloc[8,0])&(df1["set_1"]==df2.iloc[8,1])].sum()["par"]
k1=df1[(df1["group"]==df2.iloc[9,0])&(df1["set_2"]==df2.iloc[9,1])].sum()["val"]
k2=df1[(df1["group"]==df2.iloc[9,0])&(df1["set_2"]==df2.iloc[9,1])].sum()["par"]
l1=df1[(df1["group"]==df2.iloc[10,0])&(df1["set_2"]==df2.iloc[10,1])].sum()["val"]
l2=df1[(df1["group"]==df2.iloc[10,0])&(df1["set_2"]==df2.iloc[10,1])].sum()["par"]
m1=df1[(df1["group"]==df2.iloc[11,0])&(df1["set_4"]==df2.iloc[11,1])].sum()["val"]
m2=df1[(df1["group"]==df2.iloc[11,0])&(df1["set_4"]==df2.iloc[11,1])].sum()["par"]
n1=df1[(df1["group"]==df2.iloc[12,0])&(df1["set_4"]==df2.iloc[12,1])].sum()["val"]
n2=df1[(df1["group"]==df2.iloc[12,0])&(df1["set_4"]==df2.iloc[12,1])].sum()["par"]

До этого момента мне приходилось вручную создавать пары "val" и "par" для каждого элемента.Тогда

a=a1/a2
b=b1/b2
c=c1/c2
d=d1/d2
e=e1/e2
f=f1/f2
g=g1/g2
h=h1/h2
j=j1/j2
k=k1/k2
l=l1/l2
m=m1/m2
n=n1/n2

Наконец, результат:

df2["desired_calculation"]=[a,b,c,d,e,f,g,h,j,k,l,m,n]