Oracle SQL Sum с условиями

Question

Я пытаюсь суммировать (текущие часы), (часы болезни) по отделам и месяцам. В эту сумму должен входить отдел, в котором они работают, в который я включил описание случая. Однако я несколько раз пытался сделать это сам, но не могу заставить его работать так, как ожидалось.

EMP_NO     Wage_type     Hours_worked   Department      OBJID(UNIQUE)  DATE
10011      Normal        14             1063            ABC116         04/01/18
10011      Normal        07             1063            ABC117         05/01/18
10011      SICK          21             1063            ABC118         01/02/18
10030      Normal        12.5           1054            ABC119         02/02/18
10030      SICK          7              1054            ABC120         03/02/18
10030      SICK          7              1054            ABC121         04/02/18

Пример кода для необработанных данных и т. Д .:

Select 
 TPDRS.OBJID
,TPDRS.WAGE_HOURS
,(case 
    when TPDRS.ORG_CODE = 1010 then  'Trolley P1'
    when TPDRS.ORG_CODE = 1011 then  'Trolley P2'
    when TPDRS.ORG_CODE = 1053 then  'Trolley P3'
    when TPDRS.ORG_CODE between 1054 and 1057 then  'Trolley P4'
    when TPDRS.ORG_CODE between 1040 and 1047 then  'Trolley P5'
    when TPDRS.ORG_CODE in ('1063','1064','1065','1068') then 'Trolley P6'
    else 'NOT REQUIRED'
        end) as Department
,TPDRS.EMP_NO
,TPDRS.ACCOUNT_DATE
,EXTRACT(Month from TPDRS.ACCOUNT_DATE) "Month_Number"
,EXTRACT(Year from TPDRS.ACCOUNT_DATE) "Year"

from TrolleyParkAttendant  TPDRS
WHERE TPDRS.ACCOUNT_DATE > '01/DEC/2017'
 AND (TPDRS.WAGE_GRP_DB IN ( 'O', 'N' ) or WAGE_CODE = 'SICK')

---

Expected Results:
Department    HoursSick     HoursPresent     Month
Trolley P6      0             21              01
Trolley P6     21             0               02 
Trolley P3     14             12.5            02

Любая помощь будет оценена

Answer 1

Вы можете использовать следующий оператор SQL с conditional aggregation

SELECT decode(1063,'Trolley P6',1054,'Trolley P3') as Department,
       sum(case when Wage_type='SICK' then Hours_worked end) as HoursSick,
       sum(case when Wage_type='Normal' then Hours_worked end) as HoursPresent,
       to_char(TPDRS.ACCOUNT_DATE,'mm') as "Month"       
  FROM TrolleyParkAttendant  TPDRS
 WHERE TPDRS.ACCOUNT_DATE > '01/DEC/2017'
   AND (TPDRS.WAGE_GRP_DB IN ( 'O', 'N' ) or WAGE_CODE = 'SICK')
 GROUP BY decode(1063,'Trolley P6',1054,'Trolley P3'), 
          to_char(TPDRS.ACCOUNT_DATE,'mm');

Answer 2

Кажется, что в вашей модели данных отсутствуют таблица отделов и таблица организации. Вы должны, вероятно, создать их. Ну, CTE (WITH предложение) пока подойдет ...

with dept as
(
  select 'P1' as id, 'Trolley P1' as name from dual union all
  select 'P2' as id, 'Trolley P2' as name from dual union all
  select 'P3' as id, 'Trolley P3' as name from dual union all
  select 'P4' as id, 'Trolley P4' as name from dual union all
  select 'P4' as id, 'Trolley P5' as name from dual union all
  select 'P6' as id, 'Trolley P6' as name from dual
)
, org as
(
  select 1010 as code, 'P1' as dept_id from dual union all
  select 1011 as code, 'P2' as dept_id from dual union all
  select 1053 as code, 'P3' as dept_id from dual union all
  select 1054 as code, 'P4' as dept_id from dual union all
  select 1057 as code, 'P4' as dept_id from dual union all
  select 1040 as code, 'P5' as dept_id from dual union all
  select 1047 as code, 'P5' as dept_id from dual union all
  select 1063 as code, 'P6' as dept_id from dual union all
  select 1064 as code, 'P6' as dept_id from dual union all
  select 1065 as code, 'P6' as dept_id from dual union all
  select 1068 as code, 'P6' as dept_id from dual
)
select
  dept.name as department,
  sum(case when tpa.wage_code = 'SICK' then wage_hours end) as hours_sick,
  sum(case when tpa.wage_grp_db in ('O', 'N') then wage_hours end) as hours_present,
  to_char(account_date, 'yyyy-mm') as month
from trolleyparkattendant tpa
join org on org.code = tpa.org_code
join dept on dept.id = org.dept_id
group by dept.name, to_char(account_date, 'yyyy-mm') 
order by month, department;

Я взял wage_grp_db in ('O', 'N') и wage_code = 'SICK', чтобы быть взаимоисключающими. Ваше WHERE предложение вроде бы подсказало это. Возможно, вам придется принять это, если это не так.

Если вы тоже хотите посчитать записи, не относящиеся к отделам, тогда вместо этого введите left outer join dept.

Answer 3

Требуется условное агрегирование, чтобы избежать повторения выражений, вложенных в производную таблицу ( Встроенное представление на языке Oracle):

select
    Department
  ,sum(case when Wage_type = 'SICK' then Hours_worked else 0 end) as HoursSick
  ,sum(case when Wage_type = 'Normal' then Hours_worked else 0 end) as HoursPresent
  ,"Month_Number"
  ,"Year"
from
 (
    Select 
     (case 
        when TPDRS.ORG_CODE = 1010 then  'Trolley P1'
        when TPDRS.ORG_CODE = 1011 then  'Trolley P2'
        when TPDRS.ORG_CODE = 1053 then  'Trolley P3'
        when TPDRS.ORG_CODE between 1054 and 1057 then  'Trolley P4'
        when TPDRS.ORG_CODE between 1040 and 1047 then  'Trolley P5'
        when TPDRS.ORG_CODE in ('1063','1064','1065','1068') then 'Trolley P6'
        else 'NOT REQUIRED'
            end) as Department
    ,EXTRACT(Month from TPDRS.ACCOUNT_DATE) "Month_Number"
    ,EXTRACT(Year from TPDRS.ACCOUNT_DATE) "Year"

    from TrolleyParkAttendant  TPDRS
    WHERE TPDRS.ACCOUNT_DATE > '01/DEC/2017'
     AND (TPDRS.WAGE_GRP_DB IN ( 'O', 'N' ) or WAGE_CODE = 'SICK')
 ) dt
group by
    Department
  ,"Month_Number"
  ,"Year"