сравнивая с датами?

Question

Использование SQL Server 2000

Table1

ID Name, Date, TimeIn, TimeOut, DateIn, Dateout

AEAA00294 Alexander 13/10/2008 09:00:00 18:00:00 13/10/2008 13/10/2008
AEAA00294 Alexander 14/10/2008 16:00:00 02:00:00 14/10/2008 15/10/2008
AEAA00294 Alexander 16/10/2008 09:00:00 18:00:00 16/10/2008 16/10/2008

Итак ...,

Table2

ID Date

DATE, TIME, ID

20081013 103417 AEAA00294
20081013 151552 AEAA00294
20081013 170836 AEAA00294
20081013 170909 AEAA00294
20081013 171015 AEAA00294
20081014 163648 AEAA00294
20081014 030838 AEAA00294
20081015 144708 AEAA00294
20081015 151133 AEAA00294
20081016 095211 AEAA00294

Итак ...,

Из приведенных выше двух таблиц я беру Интайм, который является минимальным (время) в качестве Интайма на дату и максимальным (время) в качестве Интервала на ту же дату из таблицы2, где table1.personid = table2.personid.

In table1 DateIn and Dateout Date is same, it should take min (time) and Max (time) on the same date from the table2

Suppose table1 DateIn and Dateout Date is different, it should take min (time) and Max (time) from table2 compare with table1.dateIn and table2.Dateout

Ожидаемый результат

ID Date Intime Outtime

AEAA00294 20081013 103417 171015
AEAA00294 20081014 030838 151133

Итак ...,

Мой запрос

SELECT DISTINCT DERIVEDTBL.PERSONID, DERIVEDTBL.CARDEVENTDATE, MIN(DERIVEDTBL.CARDEVENTTIME) AS INTIME, MAX(DERIVEDTBL.CARDEVENTTIME) AS OUTTIME, tmp_Cardevent1.Normal_Intime, tmp_Cardevent1.Normal_Outtime, tmp_Cardevent1.CardEventDate AS Expr1, tmp_Cardevent1.DateIn, tmp_Cardevent1.DateOut FROM (SELECT     T_PERSON.PERSONID, T_CARDEVENT.CARDEVENTDATE, CONVERT(VARCHAR(10), SUBSTRING(T_CARDEVENT.CARDEVENTTIME, 1, 2) + ':' + SUBSTRING(T_CARDEVENT.CARDEVENTTIME, 3, 2) + ':' + SUBSTRING(T_CARDEVENT.CARDEVENTTIME, 5, 2), 8) AS CARDEVENTTIME
FROM T_CARDEVENT LEFT JOIN T_PERSON ON T_CARDEVENT.PERSONID = T_PERSON.PERSONID) DERIVEDTBL INNER JOIN tmp_Cardevent1 ON DERIVEDTBL.PERSONID = tmp_Cardevent1.PERSONID AND DERIVEDTBL.CARDEVENTDATE = tmp_Cardevent1.CardEventDate GROUP BY DERIVEDTBL.CARDEVENTDATE, DERIVEDTBL.PERSONID, tmp_Cardevent1.Normal_Intime, tmp_Cardevent1.Normal_Outtime, tmp_Cardevent1.CardEventDate, tmp_Cardevent1.DateIn, tmp_Cardevent1.DateOut

Table1 в качестве tmp_cardevent1 и Table2 в качестве Derivedtbl в моем запросе.

Исходя из вышеизложенного, я хочу сравнить производную дату со значениями tmp_cardevent1 dateIn и DateOut.

Нужна помощь по запросу.

Как сделать запрос для этого условия?

Answer 1

Попробуйте что-то вроде этого

DECLARE @Table1 TABLE(
        ID VARCHAR(50),
        PNAME VARCHAR(50),
        Date DATETIME,
        TimeIN VARCHAR(10),
        [TimeOut] VARCHAR(10),
        DateIn DATETIME,
        DateOut DATETIME
)

INSERT INTO @Table1 (ID,PNAME,Date,TimeIN,[TimeOut],DateIn,DateOut)
SELECT 'AEAA00294','Alexander','13 Oct 2008', '09:00:00', '18:00:00','13 Oct 2008','13 Oct 2008'
INSERT INTO @Table1 (ID,PNAME,Date,TimeIN,[TimeOut],DateIn,DateOut)
SELECT 'AEAA00294','Alexander','14 Oct 2008', '16:00:00', '02:00:00','14 Oct 2008','15 Oct 2008'
INSERT INTO @Table1 (ID,PNAME,Date,TimeIN,[TimeOut],DateIn,DateOut)
SELECT 'AEAA00294','Alexander','16 Oct 2008', '09:00:00', '18:00:00','16 Oct 2008','16 Oct 2008'

DECLARE @Table2 TABLE(
        Date DATETIME,
        [Time] VARCHAR(10),
        ID VARCHAR(50)
)

INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008', '10:34:17', 'AEAA00294'
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '15:15:52' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '17:08:36' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '17:09:09' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '13 Oct 2008' , '17:10:15' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '14 Oct 2008' , '16:36:48' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '14 Oct 2008' , '03:08:38' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '15 Oct 2008' , '14:47:08' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '15 Oct 2008' , '15:11:33' , 'AEAA00294' 
INSERT INTO @Table2 (Date,[Time],ID) SELECT '16 Oct 2008' , '09:52:11' , 'AEAA00294' 


SELECT  t1.ID,
        t1.PNAME,
        t1.DateIn,
        t1.DateOut,
        MIN(CAST(t2In.[Time] AS DATETIME)),
        MAX(CAST(t2Out.[Time] AS DATETIME))
FROM    @Table1 t1 LEFT JOIN
        @Table2 t2IN    ON  t1.ID = t2IN.ID
                        AND t1.DateIn = t2IN.Date LEFT JOIN
        @Table2 t2Out   ON  t1.ID = t2Out.ID
                        AND t1.DateOut = t2Out.Date
GROUP BY t1.ID,
        t1.PNAME,
        t1.DateIn,
        t1.DateOut

Answer 2

Я думаю, что это сделает это:

update table1 set timein=t2.timein, timeout=t2.timeout from table1 t1 join
(select ID, date, min(time) as timein, max(time) as timeout from table2 group by is, date) as t2 on t1.id=t2.id