Я застрял с Sf4:
Я хочу сделать систему аутентификации без FOS, но когда я хочу сделать функцию reset-pwd, у меня появляется эта ошибка:
Argument 1 passed to UserPasswordEncoder::encodePassword() must implement interface UserInterface, array given, called in SecurityController.php on line 56
МойSecurityController.php:
<?php
namespace App\Controller;
use App\Form\ChangePasswordType;
use App\Entity\User;
use App\Repository\UserRepository;
use Symfony\Bundle\FrameworkBundle\Controller\AbstractController;
use Symfony\Component\HttpFoundation\Response;
use Symfony\Component\HttpFoundation\Request;
use Symfony\Component\Routing\Annotation\Route;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Component\Security\Core\Encoder\UserPasswordEncoderInterface;
use Symfony\Component\Security\Http\Authentication\AuthenticationUtils;
class SecurityController extends AbstractController {
public function login(AuthenticationUtils $helper): Response {
return $this->render('security/login.html.twig', [
// dernier username saisi (si il y en a un)
'last_username' => $helper->getLastUsername(),
// La derniere erreur de connexion (si il y en a une)
'error' => $helper->getLastAuthenticationError(),
]);
}
public function logout(): void {
throw new \Exception('This should never be reached!');
}
public function resetpwd (Request $request, UserPasswordEncoderInterface $encoder) {
$manager = $this->getDoctrine()->getManager();
$changePassword = $request->request->get('change_password');
$username = $changePassword['username'];
$password = $changePassword['password']['first'];
$user = new User();
$user = $manager->getRepository(User::class)->findBy(['username' => $username]);
if (!$username) {
$this->addFlash('danger', 'User not found for '. $username);
}
$form = $this->createForm(ChangePasswordType::class, $user);
$form->handleRequest($request);
if ($form->isSubmitted() && $form->isValid()) {
try {
$pass = $encoder->encodePassword($user, $password);
$user->setPassword($pass);
$manager->flush();
$this->addFlash('success', 'Password Changed!');
} catch (Exception $e) {
$this->addFlash('danger', 'Something went skew-if. Please try again.');
}
return $this->redirectToRoute('athena_restepwd');
}
return $this->render('security/reset.html.twig', array('form' => $form->createView()));
}
}
Моя учетная запись:
<?php
namespace App\Entity;
use Doctrine\ORM\Mapping as ORM;
use Symfony\Component\Security\Core\User\UserInterface;
use Symfony\Bridge\Doctrine\Validator\Constraints\UniqueEntity;
use Symfony\Component\Validator\Constraints as Assert;
/**
* @ORM\Entity(repositoryClass="App\Repository\UserRepository")
* @ORM\Table(name="user")
* @UniqueEntity(fields="email", message="Email déjà pris")
* @UniqueEntity(fields="username", message="Username déjà pris")
*/
class User implements UserInterface, \Serializable {
/**
* @var int
*
* @ORM\Id
* @ORM\GeneratedValue
* @ORM\Column(type="integer")
*/
private $id;
/**
* @var string
*
* @ORM\Column(type="string")
* @Assert\NotBlank()
*/
private $fullName;
/**
* @var string
*
* @ORM\Column(type="string", unique=true)
* @Assert\NotBlank()
*/
private $username;
/**
* @var string
*
* @ORM\Column(type="string", unique=true)
* @Assert\NotBlank()
* @Assert\Email()
*/
private $email;
/**
* @var string
*
* @ORM\Column(type="string", length=64)
*/
private $password;
/**
* @var array
*
* @ORM\Column(type="array")
*/
private $roles = [];
public function getId(): int {
return $this->id;
}
public function setFullName(string $fullName): void {
$this->fullName = $fullName;
}
public function getFullName(): ?string {
return $this->fullName;
}
public function getUsername(): ?string {
return $this->username;
}
public function setUsername(string $username): void {
$this->username = $username;
}
public function getEmail(): ?string {
return $this->email;
}
public function setEmail(string $email): void {
$this->email = $email;
}
public function getPassword(): ?string {
return $this->password;
}
public function setPassword(string $password): void {
$this->password = $password;
}
/**
* Retourne les rôles de l'user
*/
public function getRoles(): array {
$roles = $this->roles;
// Afin d'être sûr qu'un user a toujours au moins 1 rôle
if (empty($roles)) {
$roles[] = 'ROLE_USER';
}
return array_unique($roles);
}
public function setRoles(array $roles): void {
$this->roles = $roles;
}
/**
* Retour le salt qui a servi à coder le mot de passe
*
* {@inheritdoc}
*/
public function getSalt(): ?string {
// See "Do you need to use a Salt?" at https://symfony.com/doc/current/cookbook/security/entity_provider.html
// we're using bcrypt in security.yml to encode the password, so
// the salt value is built-in and you don't have to generate one
return null;
}
/**
* Removes sensitive data from the user.
*
* {@inheritdoc}
*/
public function eraseCredentials(): void {
// Nous n'avons pas besoin de cette methode car nous n'utilions pas de plainPassword
// Mais elle est obligatoire car comprise dans l'interface UserInterface
// $this->plainPassword = null;
}
/**
* {@inheritdoc}
*/
public function serialize(): string {
return serialize([$this->id, $this->username, $this->password]);
}
/**
* {@inheritdoc}
*/
public function unserialize($serialized): void {
[$this->id, $this->username, $this->password] = unserialize($serialized, ['allowed_classes' => false]);
}
}
Я также попытался создать второго фальшивого пользователя с $user2 = new User(); и использовать его на $pass = $encoder->encodePassword($user, $password); при изменении сообщения об ошибкеto: Вызов функции-члена setPassword () для массива , поэтому я думаю, что моя сущность неверна, но я обнаружил свою ошибку
Regard,