Хорошо, вот что у меня есть.Не элегантно, но я думаю, что это делает работу.
import datetime
import pandas as pd
import random
# Sample dataset
df = pd.DataFrame({'Date':sorted([datetime.date.today() - datetime.timedelta(days=i) for i in range(80)]), 'Price':[i for i in range(80)]})
df['Price'] = df['Price'].apply(lambda x: random.uniform(80,100))
>>>df
Date Price
0 2018-11-11 83.894664
1 2018-11-12 86.472656
2 2018-11-13 92.566676
3 2018-11-14 94.145586
.. ... ...
77 2019-01-27 86.338076
78 2019-01-28 95.374173
79 2019-01-29 98.829077
[80 rows x 2 columns]
# MA calculation - borrowing from @jezrael's solution at /10475771/kak-mne-vypolnit-skolzyaschuy-srednyy-v-pande-s-kolonkoi-kotoraya-dolzhna-byt-unikalnoi#10475776
seq = df.set_index('Date')['Price'].rolling(50).mean().rename('MA')
df = df.join(seq, on='Date')
# Set buy signals if current price is higher than 50-day MA
df['Buy'] = df['Price'] - df['MA'] > 0
# Lookbehind check to see that it was below MA at T-1
df['BelowMA'] = df['Price'] - df['MA'] <= 0
# Profit calculations
df['Profit'] = (df['Price'] - df['Price'].shift(-3))/df['Price']
И, наконец, строки, которые удовлетворяют заданным ограничениям
>>> df.loc[(df['BelowMA'].shift(1)==True) & (df['Buy'] == True)]
Date Price MA Buy Profit BelowMA
54 2019-01-04 91.356371 89.634529 True 0.000697 False
56 2019-01-06 94.116616 89.623909 True 0.114375 False
60 2019-01-10 89.383369 89.254519 True -0.082870 False
63 2019-01-13 96.790575 88.977660 True 0.029314 False
69 2019-01-19 92.193939 89.052057 True 0.071259 False
74 2019-01-24 91.392465 89.302293 True 0.020673 False
76 2019-01-26 95.369195 89.292715 True 0.158250 False