Javascript получить рабочие дни между двумя конкретными рабочими днями

Question

Как я могу получить все названия дней недели между 2 днями в качестве параметров?Это должно также возвратиться точно, когда это пройдет 7 дней.

Формат моей недели:

«Воскресенье», «Понедельник», «Вторник», «Среда», «Четверг», «Пятница», «Суббота»

Пример и ожидаемый результат ниже.Спасибо

function day(first, last) {
  var day = new Date();
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');

  for (i = 0; i < 14; i++) {
    console.log(week[(day.getDay() + 1 + i) % 7]);
  }

}

day('Tuesday', 'Thursday'); // output should be "Tuesday, Wednesday, Thursday"
day('Friday', 'Tuesday'); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
day('Saturday', 'Monday'); // output should be "Saturday, Sunday, Monday"

Answer 1

Я думаю, вы должны установить индекс для каждого дня недели.

function day(first, last) {
    var firstIndex;
    var lastIndex;
    var weekDays = [
        { index: 0, name: 'Monday' },
        { index: 1, name: 'Tuesday' },
        { index: 2, name: 'Wednesday' },
        { index: 3, name: 'Thursday' },
        { index: 4, name: 'Friday' },
        { index: 5, name: 'Saturday' },
        { index: 6, name: 'Sunday' }
    ];

    weekDays.forEach(function (item) {
        firstIndex = item.name.toLowerCase() === first.toLowerCase() ? item.index : firstIndex;
        lastIndex = item.name.toLowerCase() === last.toLowerCase() ? item.index : lastIndex;
    });

    if (firstIndex === undefined || lastIndex === undefined) { return; }

    var days = [];
    weekDays.forEach(function (item) {
        if (item.index >= firstIndex && item.index <= lastIndex) {
            days.push(item.name);
        }
    });

    console.log(days.join(', '));
}

Answer 2

Просто, но очевидно и эффективно:

function day(first, last) {
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday', 'Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  var found = false; 
  for(var i=0; i<week.length; i++) {
    if (!found) {
        if (week[i] == first) found = true;
    }
    if (found) {
        console.log(week[i]);
    }
    if (found && week[i] == last) {
        return;
    }
  }
}

Попробуйте онлайн!

Answer 3

Попробуйте вот так

function GetDays(first, last) {
  var day = new Date();
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  var start_index=week.indexOf(first);
  var last_index=week.indexOf(last);
  if(start_index<last_index){
     return week.slice(start_index,last_index+1);
  }
  else{
     return [...week.slice(start_index),...week.slice(0,last_index+1)]
  }
}
console.log(GetDays("Sunday","Tuesday"))
console.log(GetDays("Sunday","Sunday"))

Answer 4

function day(first, last) {
    var day = new Date();
    var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
	var firstIdx = week.indexOf(first), lastIdx = week.indexOf(last);

	var result = [];
	if(lastIdx >= firstIdx) {
		for (var i = firstIdx; i <= lastIdx && i < week.length; i++)
			result.push(week[i]);
	}
	else {
		for (var i = firstIdx; i < week.length; i++)
			result.push(week[i]);
		for (var i = 0; i <= lastIdx && i < week.length; i++)
			result.push(week[i]);
	}
	return result;
}

alert(day('Tuesday', 'Thursday')); // output should be "Tuesday, Wednesday, Thursday"
alert(day('Friday', 'Tuesday')); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
alert(day('Saturday', 'Monday')); // output should be "Saturday, Sunday, Monday"

Answer 5

function day(first, last) {
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');

  for (i = 0; i < 7; i++) {
     if(week[i]==first){
        for(j=i ; i< 14 ;j++){ 
            console.log(week[j%7]);
            if(week[j]==end){
               return;
            }
        }

     }
  }

}

day('Tuesday', 'Thursday'); // output should be "Tuesday, Wednesday, Thursday"
day('Friday', 'Tuesday'); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
day('Saturday', 'Monday'); // output should be "Saturday, Sunday, Monday"

Answer 6

Вот один из способов сделать это:

function day(first, last) {
  var day = new Date();
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  //Double the array to account for going from end of the week to the beginning
  var weeks = week.concat(week);
  var dayArray = [];
  var activeDay = false;
  //Loop through the large week array. 
  for (var x=0; x<weeks.length; x++) {
     var day = weeks[x];
    //Start adding to the array on the first day
    if (day == first) {
        activeDay = true;
    }
    //Start adding to the array on the first day
    if (activeDay) {
        dayArray.push(day);
      //If the last day then exit
      if (day == last) {
        return dayArray;
      }
    }

  }
    //Return an empty array if no matches
    return [];
}

day('Tuesday', 'Thursday'); // output should be "Tuesday, Wednesday, Thursday"
day('Friday', 'Tuesday'); // output should be "Friday, Saturday, Sunday, Monday, Tuesday
day('Saturday', 'Monday'); // output should be "Saturday, Sunday, Monday"

Answer 7

Думаю, я бы просто вернул два разных случая в зависимости от того, расширился ли диапазон после выходных.Это просто вернет ломтик, если начало в начале недели.В противном случае он возвращает две части по кусочкам:

function day(first, last) {
    var week = ['Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday']
    let start = week.indexOf(first)
    let end = week.indexOf(last)
    return (start > end)
        ? [...week.slice(start), ...week.slice(0, end+1)]
        : week.slice(start, end+1)
  
  }

  console.log(day('Tuesday', 'Thursday'))
  console.log(day('Friday', 'Tuesday'))
  console.log(day('Saturday', 'Monday')) 

Answer 8

Вы можете манипулировать массивом, чтобы избежать использования циклов.Код прокомментирован для ясности.

function day(first, last) {
  var week = new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');

  var firstIndex = week.indexOf(first);          //Find first day
  week = week.concat(week.splice(0,firstIndex)); //Shift array so that first day is index 0
  var lastIndex = week.indexOf(last);            //Find last day
  return week.slice(0,lastIndex+1);              //Cut from first day to last day
}

console.log(day('Tuesday', 'Thursday'));
console.log(day('Friday', 'Tuesday'));
console.log(day('Saturday', 'Monday'));

Answer 9

Примерно так:

function day(first,last) {
  var week=new Array('Sunday', 'Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday');
  var i=week.indexOf(first), result=[];
  do {
    result.push(week[i]);
    i=(i+1) % week.length;
  } while (week[i]!==last);
  result.push(last);
  return result;
}