Как извлечь каждую строку, которая соответствует только первому появлению определенного символа в этой строке?

Question

Я работаю над сценарием оболочки bash.У меня есть переменная, которая имеет ряд строк.Здесь: как извлечь каждую строку, которая соответствует символу 5 в столбце 5 ?

declare -a T1 echo '$input' T=$(echo -e "$input" | grep 5) echo "$T"

содержимое входной переменной:

:: find lo(): [5] :: Current Digital = 0.00 4
:: find lo(): [6] :: Current Digital = 0.00 4
:: find lo(): [7] :: Current Digital = 0.00 5
:: find lo(): [8] :: Current Digital = 0.00 4
:: find lo(): [5] :: Current Digital = 0.00 7
:: find lo(): [6] :: Current Digital = 0.00 7
:: find lo(): [7] :: Current Digital = 0.00 15
:: find lo(): [8] :: Current Digital = 0.00 7
:: find lo(): [5] :: Current Digital = 0.00 10
:: find lo(): [6] :: Current Digital = 0.00 10
:: find lo(): [7] :: Current Digital = 0.00 10
:: find lo(): [8] :: Current Digital = 0.00 35
:: find lo(): [5] :: Current Digital = 0.00 13
:: find lo(): [6] :: Current Digital = 0.00 25
:: find lo(): [7] :: Current Digital = 0.00 13
:: find lo(): [8] :: Current Digital = 0.00 13
:: find lo(): [5] :: Current Digital = 0.00 15
:: find lo(): [6] :: Current Digital = 0.00 50
:: find lo(): [7] :: Current Digital = 0.00 16
:: find lo(): [8] :: Current Digital = 0.00 55

Ожидаемое содержание переменной T1:

:: find lo(): [5] :: Current Digital = 0.00 4
:: find lo(): [5] :: Current Digital = 0.00 7
:: find lo(): [5] :: Current Digital = 0.00 10
:: find lo(): [5] :: Current Digital = 0.00 13
:: find lo(): [5] :: Current Digital = 0.00 15

Текущее содержание переменной T1:

:: find lo(): [5] :: Current Digital = 0.00 4
:: find lo(): [7] :: Current Digital = 0.00 5
:: find lo(): [5] :: Current Digital = 0.00 7
:: find lo(): [7] :: Current Digital = 0.00 15
:: find lo(): [5] :: Current Digital = 0.00 10
:: find lo(): [8] :: Current Digital = 0.00 35
:: find lo(): [5] :: Current Digital = 0.00 13
:: find lo(): [5] :: Current Digital = 0.00 15
:: find lo(): [6] :: Current Digital = 0.00 50
:: find lo(): [8] :: Current Digital = 0.00 55

Answer 1

Эта команда должна дать ожидаемый результат, если первое вхождение 5 всегда заключено в квадратные скобки.

T=$(echo -e "$input" | grep '\[5\]'))