Hello?Я пытаюсь написать запрос (который имеет 2 подзапроса) в SQLAlchemy, но я получаю ошибку AttributeError: у объекта list нет атрибута l_date
Вот мой код:
import sqlalchemy as db
from sqlalchemy import func
from sqlalchemy import desc
from sqlalchemy.orm import sessionmaker
from sqlalchemy import or_
from sqlalchemy import and_
from sqlalchemy.sql.expression import alias
try:
engine = db.create_engine('postgresql://user:pass@localhost:5432/db_name')
connection = engine.connect()
except:
print('Error establishing DB connection')
# Import metadata
metadata = db.MetaData()
# create a configured "Session" class
Session = sessionmaker(bind=engine)
# create a Session
session = Session()
# Import articles, authors and log tables
log = db.Table('log', metadata, autoload=True, autoload_with=engine)
def days_with_request_errors():
query1 = db.select([func.DATE(log.columns.time).label('l_date'), func.count(log.columns.status).label('s_count')]) \
.where(or_(log.columns.status.like('%5%'), log.columns.status.like('%4%'))) \
.group_by(func.DATE(log.columns.time))
ResultProxy = connection.execute(query1)
q1 = ResultProxy.fetchall()
query2 = db.select([func.DATE(log.columns.time).label('l_date'),
func.count(log.columns.status).label('s_count')]) \
.group_by(func.DATE(log.columns.time))
ResultProxy = connection.execute(query2)
q2 = ResultProxy.fetchall()
main_query = db.select([q1.l_date, (q1.s_count * 100) / q2.s_count]) \
.where(q1.l_date == q2.l_date) \
.where(and_((q1.c.s_count * 100) / q2.c.s_count) > 1)
ResultProxy = connection.execute(main_query)
return ResultProxy.fetchall()
Вот необработанный запрос SQL, который я передаю в SQLAlchemy.(Необработанный запрос работает нормально):
SELECT q1.date, ((q1.count * 100) / q2.count) as percentage
FROM (SELECT date(time) as date, COUNT(status) as count
FROM log
WHERE status LIKE '%4%' or status LIKE '%5%'
GROUP BY date(time)) as q1,
(SELECT date(time) as date, COUNT(status) as count
FROM log
GROUP BY date(time)) as q2
WHERE q1.date = q2.date and ((q1.count * 100) / q2.count) > 1
Любая помощь будет принята с благодарностью.