Ошибка изображения в браузере
Это код в моем скрипте веб-приложения Google, и doPost определен, но я получаю ту же ошибку, и мои листы Google не регистрируют вводпользователя "undefined"
// original from: http://mashe.hawksey.info/2014/07/google-sheets-as-a-database-insert-with-apps-script-using-postget-methods-with-ajax-example/
function doGet(e){
return handleResponse(e);
}
// Usage
// 1. Enter sheet name where data is to be written below
var SHEET_NAME = "Sheet1";
// 2. Run > setup
//
// 3. Publish > Deploy as web app
// - enter Project Version name and click 'Save New Version'
// - set security level and enable service (most likely execute as 'me' and access 'anyone, even anonymously)
//
// 4. Copy the 'Current web app URL' and post this in your form/script action
//
// 5. Insert column names on your destination sheet matching the parameter names of the data you are passing in (exactly matching case)
var SCRIPT_PROP = PropertiesService.getScriptProperties(); // new property service
// If you don't want to expose either GET or POST methods you can comment out the appropriate function
function doPost(e){
return handleResponse(e);
}
function handleResponse(e) {
// shortly after my original solution Google announced the LockService[1]
// this prevents concurrent access overwritting data
// [1] http://googleappsdeveloper.blogspot.co.uk/2011/10/concurrency-and-google-apps-script.html
// we want a public lock, one that locks for all invocations
var lock = LockService.getPublicLock();
lock.waitLock(30000); // wait 30 seconds before conceding defeat.
try {
// next set where we write the data - you could write to multiple/alternate destinations
var doc = SpreadsheetApp.openById(SCRIPT_PROP.getProperty("key"));
var sheet = doc.getSheetByName(SHEET_NAME);
// we'll assume header is in row 1 but you can override with header_row in GET/POST data
var headRow = e.parameter.header_row || 1;
var headers = sheet.getRange(1, 1, 1, sheet.getLastColumn()).getValues()[0];
var nextRow = sheet.getLastRow()+1; // get next row
var row = [];
// loop through the header columns
for (i in headers){
if (headers[i] == "Timestamp"){ // special case if you include a 'Timestamp' column
row.push(new Date());
} else { // else use header name to get data
row.push(e.parameter[headers[i]]);
}
}
// more efficient to set values as [][] array than individually
sheet.getRange(nextRow, 1, 1, row.length).setValues([row]);
// return json success results
return ContentService
.createTextOutput("Success")
.setMimeType(ContentService.MimeType.TEXT);
} catch(e){
// if error return this
return ContentService
.createTextOutput("Failure")
.setMimeType(ContentService.MimeType.TEXT);
} finally { //release lock
lock.releaseLock();
}
}
function setup() {
var doc = SpreadsheetApp.getActiveSpreadsheet();
SCRIPT_PROP.setProperty("key", doc.getId())
;}
Гугл листы
Это еще одна ошибка, которую я не понимаю.В моем HTML-коде я определил мои пользовательские данные в точности так, как они показаны в каждой ячейке, которую я создал на листах.