Очень простой вопрос.Я использую лист Excel, который имеет три строки для заголовков столбцов;как я могу преобразовать эти два заголовка строки в один (используя library(formattable))?Кроме того, эти заголовки не начинаются в верхней части листа.Спасибо
Мои данные
dput(tab )
structure(list(X = c(NA, 1L, 2L, 3L, 6L, 7L, 8L, 9L, 10L, 11L,
12L, 13L, 21L, 23L, 41L, 42L, 43L, 44L, 46L, 49L, 61L, 63L, 71L,
73L, 82L, 92L, 100L, 111L), Activities = c("Label", "Personal care (1 code)",
"Employment (1 code)", "Study (1 code)", "Social care (1 code)",
"Sports and outdoor activities (1 code)", "Hobbies, games and computing (1 code)",
"Mass media (1 code)", "Travel and unspecified time use (1 code)",
"Sleep (3 codes)", "Eating (1 code)", "Other personal care (3 codes)",
"Main Job(3 codes)", "Activities related to employment (5 codes)",
"Food Management (5 codes)", "Informal help to other households (23 codes)",
"Making care for textiles (5 codes)", "Gardening and pet care",
"Shopping and services (11 codes)", "Help to an adult household member (8 codes)",
"Social life (6 codes)", "Resting-Time out (1 code)", "Physical exercise (20 codes)",
"Games (3 codes)", "Computing (10 codes)", "TV and Video (8 codes)",
"Travel by purpose (30 codes)", " Punctuating activity(e.g. Unspecified time use, 8 codes)"
), Single = c("weighted indegree", "0", "0", "0", "0", "0", "0",
"0", "0", "0.235837", "0.38816", "0.076923", "0.243461", "0",
"0.188502", "1", "0", "0", "0", "0", "0.111111", "0.111111",
"0.246246", "0", "0.125", "0.125", "0.380399", "0.535398"), X.1 = c("weighted outdegree",
"0", "0.625", "0.076923", "1", "0.333333", "0", "0.102564", "0.619469",
"0", "0", "0.110837", "0", "0.336016", "0.13816", "0", "0", "0",
"0.095665", "0.085938", "0", "0", "0", "0.243243", "0", "0",
"0", "0"), Couple = c("weighted indegree", "0", "0", "0", "0",
"0", "0", "0", "0", "0.108846", "0.384462", "0.128419", "0.159138",
"0", "0.18836", "0", "0", "0", "0", "0", "0", "0", "0.121739",
"0", "0", "0.056196", "0.370312", "0.342532"), X.2 = c("weighted outdegree",
"0", "0", "0", "0", "0", "0.071429", "0.069444", "0.475649",
"0", "0", "0.215333", "0", "0.220292", "0.19494", "0.059706",
"0.059423", "0", "0.087323", "0.128205", "0", "0", "0", "0.278261",
"0", "0", "0", "0"), Family = c("weighted indegree", "0", "0",
"0", "0", "0", "0", "0", "0", "0.111111", "0.407475", "1", "0.432143",
"0", "0.238228", "0", "0", "0.2", "0.076923", "0", "0", "0",
"0.172414", "0", "0", "0.076923", "0.564185", "0.682906"), X.3 = c("weighted outdegree",
"1", "0.8", "0.307692", "0", "0", "0", "0.135135", "0.58547",
"0", "0", "0.111111", "0", "0.343254", "0.130552", "0", "0",
"0", "0.083931", "0.103093", "0", "0", "0", "0.362069", "0",
"0", "0", "0")), .Names = c("X", "Activities", "Single", "X.1",
"Couple", "X.2", "Family", "X.3"), class = "data.frame", row.names = c(NA,
-28L))
Как выглядит таблица:
И как бы я хотелиметь мой стол
