Проблема сопоставления абстрактного класса с пружинными данными: org.hibernate.QueryException: не удалось разрешить свойство: type_org из

Question

Я пытаюсь получить данные таблицы, созданной с помощью Spring Data JPA, рассматриваемая таблица относится к абстрактному классу, который имеет поле дискриминатора «type_org» для идентификации подклассов, но, к сожалению, когда я пытаюсь получитьданные, основанные на этом поле дискриминатора, показывают следующую ошибку:

org.hibernate.QueryException: could not resolve property: type_org of: gn.traore.demo.entities.Organisation
    at org.hibernate.persister.entity.AbstractPropertyMapping.propertyException(AbstractPropertyMapping.java:73) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.persister.entity.AbstractPropertyMapping.toType(AbstractPropertyMapping.java:67) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.persister.entity.AbstractEntityPersister.toType(AbstractEntityPersister.java:1982) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.tree.FromElementType.getPropertyType(FromElementType.java:393) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.tree.FromElement.getPropertyType(FromElement.java:509) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.tree.DotNode.getDataType(DotNode.java:687) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.tree.DotNode.prepareLhs(DotNode.java:270) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.tree.DotNode.resolve(DotNode.java:210) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.HqlSqlWalker.resolve(HqlSqlWalker.java:1045) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.expr(HqlSqlBaseWalker.java:1290) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.exprOrSubquery(HqlSqlBaseWalker.java:4706) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.comparisonExpr(HqlSqlBaseWalker.java:4174) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.logicalExpr(HqlSqlBaseWalker.java:2138) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.whereClause(HqlSqlBaseWalker.java:815) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.query(HqlSqlBaseWalker.java:609) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.selectStatement(HqlSqlBaseWalker.java:313) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.antlr.HqlSqlBaseWalker.statement(HqlSqlBaseWalker.java:261) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.analyze(QueryTranslatorImpl.java:271) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    at org.hibernate.hql.internal.ast.QueryTranslatorImpl.doCompile(QueryTranslatorImpl.java:191) ~[hibernate-core-5.3.7.Final.jar:5.3.7.Final]
    ... 205 common frames omitted

Вот абстрактный класс:

@Entity
@Inheritance(strategy=InheritanceType.SINGLE_TABLE)
@DiscriminatorColumn(name="TYPE_ORG",discriminatorType=DiscriminatorType.STRING, length=4)
public abstract class Organisation implements Serializable {

    private static final long serialVersionUID = 1L;

    @Id @GeneratedValue
    private Long id;
    private String nom;
    private String email;
    private String adresse;

    @OneToOne(mappedBy = "organisation")
    private Compte compte;

    @JsonIgnore
    @ManyToOne
    @JoinColumn(name="id_admin_PLTF")
    private AdminPlateforme adminPLTF;

    /**
     * 
     */
    public Organisation() {
        super();
        // TODO Auto-generated constructor stub
    }

    /**
     * @param nom
     * @param email
     * @param adresse
     */
    public Organisation(String nom, String email, String adresse, AdminPlateforme adminPLTF) {
        super();
        this.nom = nom;
        this.email = email;
        this.adresse = adresse;
        this.adminPLTF = adminPLTF;
    }

    /**
     * @return the id
     */
    public Long getId() {
        return id;
    }

    /**
     * @param id the id to set
     */
    public void setId(Long id) {
        this.id = id;
    }

    /**
     * @return the nom
     */
    public String getNom() {
        return nom;
    }

    /**
     * @param nom the nom to set
     */
    public void setNom(String nom) {
        this.nom = nom;
    }

    /**
     * @return the email
     */
    public String getEmail() {
        return email;
    }

    /**
     * @param email the email to set
     */
    public void setEmail(String email) {
        this.email = email;
    }

    /**
     * @return the adresse
     */
    public String getAdresse() {
        return adresse;
    }

    /**
     * @param adresse the adresse to set
     */
    public void setAdresse(String adresse) {
        this.adresse = adresse;
    }

    /**
     * @return the compte
     */
    public Compte getCompte() {
        return compte;
    }

    /**
     * @param compte the compte to set
     */
    public void setCompte(Compte compte) {
        this.compte = compte;
    }

    /**
     * @return the adminPLTF
     */
    public AdminPlateforme getAdminPLTF() {
        return adminPLTF;
    }

    /**
     * @param adminPLTF the adminPLTF to set
     */
    public void setAdminPLTF(AdminPlateforme adminPLTF) {
        this.adminPLTF = adminPLTF;
    }   

}

А вот интерфейс DAO, содержащий запрос:

@RepositoryRestResource
public interface OrganisationRepository extends JpaRepository<Organisation, Long> {

    @Query("SELECT o FROM Organisation o WHERE o.type_org=:type")
    public Organisation findOrganisation(@Param("type")String type);
}

Любые идеи, пожалуйста ??