BIGQUERY Промежуточный итог с ARRAY Object - PullRequest
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BIGQUERY Промежуточный итог с ARRAY Object

0 голосов
/ 03 декабря 2018

У меня есть образец набора данных, как показано ниже 

WITH S AS (
SELECT 1 AS ID, 1 AS ID2, 'A' AS CODE, 10 AS VALUE
UNION ALL
SELECT 2 AS ID, 1 AS ID2, 'A' AS CODE, 10 AS VALUE
UNION ALL
SELECT 3 AS ID, 2 AS ID2, 'A' AS CODE, 10 AS VALUE
UNION ALL
SELECT 4 AS ID, 2 AS ID2, 'B' AS CODE, 10 AS VALUE
UNION ALL
SELECT 5 AS ID, 3 AS ID2, 'B' AS CODE, 10 AS VALUE
UNION ALL
SELECT 6 AS ID, 3 AS ID2, 'C' AS CODE, 10 AS VALUE
),
S2 AS
(SELECT 
ID2, CODE, SUM(VALUE) AS VALUE
FROM S
GROUP BY 1,2
)
SELECT ID2, ARRAY_AGG(STRUCT(CODE, VALUE)) FROM S2
GROUP BY 1

Мне нужно получить промежуточный итог элементов ARRAY, встроенных в вывод.Мои текущие и ожидаемые результаты следующие: 

Current Output:                 
Row ID2 f0_.CODE    f0_.VALUE       
1   3   C           10      
        B           10      
2   2   B           10      
        A           10      
3   1   A           20      

Expected Output:                    
Row ID2 f0_.CODE    f0_.VALUE   f1_.CODE    f1_VALUE
1   1   A           20          A           20
2   2   B           10          B           10
        A           10          A           30
3   3   C           10          C           10
        B           10          B           20
                                A           30

Цените ваши мысли.

1 Ответ

0 голосов
/ 04 декабря 2018 
#standardSQL
WITH S AS (
  SELECT 1 AS ID, 1 AS ID2, 'A' AS CODE, 10 AS VALUE UNION ALL
  SELECT 2 AS ID, 1 AS ID2, 'A' AS CODE, 10 AS VALUE UNION ALL
  SELECT 3 AS ID, 2 AS ID2, 'A' AS CODE, 10 AS VALUE UNION ALL
  SELECT 4 AS ID, 2 AS ID2, 'B' AS CODE, 10 AS VALUE UNION ALL
  SELECT 5 AS ID, 3 AS ID2, 'B' AS CODE, 10 AS VALUE UNION ALL
  SELECT 6 AS ID, 3 AS ID2, 'C' AS CODE, 10 AS VALUE
), S1 AS (
  SELECT A.ID2, B.CODE, MAX(A.ID) ID 
  FROM S AS A CROSS JOIN S AS B
  GROUP BY ID2, CODE
), S2 AS (
  SELECT ID2, CODE, SUM(VALUE) AS VALUE, MAX(ID) ID
  FROM S
  GROUP BY ID2, CODE
), S3 AS (
  SELECT S1.ID2, S1.CODE, IFNULL(S2.VALUE, 0) VALUE, IFNULL(S2.ID, S1.ID) ID
  FROM S1 LEFT JOIN S2 
  USING(ID2, CODE)
), S4 AS (
  SELECT ID2, CODE, VALUE, SUM(VALUE) OVER(PARTITION BY CODE ORDER BY ID) TOTAL
  FROM S3 
), S5 AS (
  SELECT ID2, ARRAY_AGG(STRUCT(CODE, VALUE)) arr1, ARRAY_AGG(STRUCT(CODE, TOTAL)) arr2
  FROM S4 
  GROUP BY ID2 
)
SELECT ID2,
  ARRAY(SELECT item FROM UNNEST(arr1) item WHERE item.VALUE != 0),
  ARRAY(SELECT item FROM UNNEST(arr2) item WHERE item.TOTAL != 0)
FROM S5
ORDER BY ID2

дает вам 

Row     ID2     f0_.CODE    f0_.VALUE   f1_.CODE    f1_.TOTAL    
1       1       A           20          A           20   
2       2       A           10          A           30   
                B           10          B           10   
3       3       B           10          A           30   
                C           10          B           20   
                                        C           10
...