Вы можете попробовать [Не проверено]:
[
{ "code" : 001,"name": "Prashant" },
{ "code" : 002,"name": "Steve" }
]
Запрос:
INSERT INTO your_table (code, name)
SELECT code,name
FROM OPENJSON(@json)
WITH (code int, name nvarchar(50))
Для чтения из объекта JSON:
{"OUTER":{"ABC":"TEST_WB_New","XYZ":"9085"}} -- Your JSON
INSERT INTO your_table_name
SELECT ABC, XYZ
FROM OPENJSON(@json)
WITH (
ABC nvarchar(50) 'strict $.OUTER.ABC',
XYZ nvarchar(50) '$.OUTER.XYZ' AS JSON
)