Ссылка в виде круглого списка сзади вперед без ссылки - PullRequest
0 голосов
/ 08 декабря 2018

Я пытаюсь реализовать номер 6 на этой картинке

Я в основном пытаюсь создать круговой связанный список, и способ сделать это - сделать ссылку сзадиузел к переднему узлу.Однако в этом примере они говорят, что не следует использовать переднюю ссылку на первый узел, поэтому я не уверен, как получить доступ к переднему узлу без передней ссылки.В методы add и remove я бы просто поместил строку кода, подобную rear.setLink(front);. Однако я не знаю, как это сделать без предварительной ссылки.Вот мой код, так как большинство из них - модифицированный код из учебника, который мы используем

          /*
           * modified code from the book
         *
    */

import java.util.LinkedList;
import java.util.Queue;


   import java.util.NoSuchElementException;
    //import edu.colorado.nodes.Node;
       public class CircularLinkedList<E> implements Cloneable {

       // File: LinkedQueue.java from the package edu.colorado.collections
  // Complete documentation is available from the LinkedQueue link in:
    //   http://www.cs.colorado.edu/~main/docs/



 // Invariant of the LinkedQueue class:
 //   1. The number of items in the queue is stored in the instance variable
 //      manyNodes.
 //   2. The items in the queue are stored in a linked list, with the front 
//      of the queue stored at the head node, and the rear of the queue at 
//      the final node.
//   3. For a non-empty queue, the instance variable front is the head 
//      reference of the linked list of items and the instance variable rear
//      is the tail reference of the linked list. For an empty queue, both 
//      front and rear are the null reference.

private int manyNodes=0; //numberOf Nodes in list initialized to 0
//private Node<E> front;
private Node<E> rear;


/**
* Initialize an empty queue.
* <b>Postcondition:</b>
*   This queue is empty.
**/   
public <Node>CircularLinkedList( )
{
  //front = null;
  rear = null;

}


/**
* Put a new a new item in this queue. 
* @param item
*   the item to be pushed onto this queue 
*  <b>Postcondition:</b>
*   The item has been pushed onto this queue.
* @exception OutOfMemoryError
*   Indicates insufficient memory for increasing the queue's capacity.
* <b>Note:</b>
*   An attempt to increase the capacity beyond
*   <CODE>Integer.MAX_VALUE</CODE> will cause the queue to fail with an
*   arithmetic overflow.
**/    
public void add(E item)
{
  Node cursor;
    if (isEmpty( ))
   {  // Insert first item.
     rear = new Node<E>(item, null);
//rear = front;
    }
   else
   {  // Insert an item that is not the first.
      rear.addNodeAfter(item);
      rear = rear.getLink( );  
      //for(cursor =rear; curs
     // rear.setLink(CircularLinkedList.listposition(0)); //make link to front creating a           circular linked List

   }
   manyNodes++;
   }


/**
* Generate a copy of this queue.
* @return
*   The return value is a copy of this queue. Subsequent changes to the
*   copy will not affect the original, nor vice versa. Note that the return
*   value must be type cast to an <CODE>LinkedQueue</CODE> before it can be used.
* @exception OutOfMemoryError
*   Indicates insufficient memory for creating the clone.
**/ 
@SuppressWarnings("unchecked")
public CircularLinkedList<E> clone( )       
{  // Clone a LinkedQueue<E>.
  CircularLinkedList<E> answer;
  Object[ ] cloneInfo;

  try
  {
     answer = (CircularLinkedList<E>) super.clone( );
  }
  catch (CloneNotSupportedException e)
  { 
     // This exception should not occur. But if it does, it would probably indicate a
     // programming error that made super.clone unavailable. The most comon error
     // The most common error would be forgetting the "Implements Cloneable"
     // clause at the start of this class.
     throw new RuntimeException
     ("This class does not implement Cloneable");
  }

  cloneInfo = Node.listCopyWithTail(rear);
 // answer.front = (Node<E>) cloneInfo[0];
  answer.rear = (Node<E>) cloneInfo[1];

  return answer;
}        


/**
* Determine whether this queue is empty.
* @return
*   <CODE>true</CODE> if this queue is empty;
*   <CODE>false</CODE> otherwise. 
**/
public boolean isEmpty( )
{
  return (manyNodes == 0);
}


/**
* Get the front item, removing it from this queue.
* <b>Precondition:</b>
*   This queue is not empty.
* @return
*   The return value is the front item of this queue, and the item has
*   been removed.
* @exception NoSuchElementException
*    Indicates that this queue is empty.
**/    
public E remove( )
{
  E answer;

  if (manyNodes == 0)
     // NoSuchElementException is from java.util and its constructor has no argument.
     throw new NoSuchElementException("Queue underflow");
 answer = rear.getData( );
 // front = front.getLink( );
  manyNodes--;
  if (manyNodes == 0)
     rear = null;
  return answer;
   //rear.setLink(front);
}


/**
* Accessor method to determine the number of itaems in this queue.
*  @return
*   the number of items in this queue
**/ 
public int size( )   
{
  return manyNodes;
}

public static void main(String[] args)
{
 CircularLinkedList c1 = new CircularLinkedList();
 c1.add(1);
 c1.add(2);
 c1.add(3);
 c1.remove();
 System.out.println("the data in the rear is " + c1.rear.getData());
 //System.out.println("the data in the front is " + c1.front.getData());
// System.out.println("the data in node after rear is  " + c1.rear.getLink().getData());
 //System.out.println("this is because the rear links to the front making the Linked List circular");
 }
}

Ниже приведен код класса узла (редактировать не нужно)

  class Node<E>
  {
  // Invariant of the Node class:
  //   1. Each node has one reference to an E Object, stored in the instance
  //      variable data.
  //   2. For the final node of a list, the link part is null.
  //      Otherwise, the  link part is a reference to the
  //      next node of the list.
  private E data;
  private Node<E> link;

/**
* Initialize a node with a specified initial data and link to the next
* node. Note that the initialLink may be the null reference,
* which indicates that the new node has nothing after it.
* @param initialData
*   the initial data of this new node
* @param initialLink
*   a reference to the node after this new node--this reference may be null
*   to indicate that there is no node after this new node.
* @postcondition
*   This node contains the specified data and link to the next node.
**/
public Node(E initialData, Node<E> initialLink)
{
  data = initialData;
  link = initialLink;
 }


/**
* Modification method to add a new node after this node.
* @param element
*   the data to place in the new node
* @postcondition
*   A new node has been created and placed after this node.
*   The data for the new node is element. Any other nodes
*   that used to be after this node are now after the new node.
* @exception OutOfMemoryError
*    Indicates that there is insufficient memory for a new
*   Node.
**/
public void addNodeAfter(E element)
{
  link = new Node<E>(element, link);
}


/**
* Accessor method to get the data from this node.
* @param - none
* @return
*   the data from this node
**/
public E getData( )
{
  return data;
}


/**
* Accessor method to get a reference to the next node after this node.
* @param - none
* @return
*   a reference to the node after this node (or the null reference if there
*   is nothing after this node)
**/
public Node<E> getLink( )
{
  return link;
}


 /**
 * Copy a list.
 * @param source
 *   the head of a linked list that will be copied (which may be
 *   an empty list in where source is null)
 * @return
 *   The method has made a copy of the linked list starting at
 *   source. The return value is the head reference for the
 *   copy.
 * @exception OutOfMemoryError
 *   Indicates that there is insufficient memory for the new list.
 **/
 public static <E> Node<E> listCopy(Node<E> source)
 {
  Node<E> copyHead;
  Node<E> copyTail;

  // Handle the special case of the empty list.
  if (source == null)
     return null;

  // Make the first node for the newly created list.
  copyHead = new Node<E>(source.data, null);
  copyTail = copyHead;

  // Make the rest of the nodes for the newly created list.
  while (source.link != null)
  {
     source = source.link;
     copyTail.addNodeAfter(source.data);
     copyTail = copyTail.link;
  }

  // Return the head reference for the new list.
  return copyHead;
}


 /**
 * Copy a list, returning both a head and tail reference for the copy.
 * @param source
 *   the head of a linked list that will be copied (which may be
 *   an empty list in where source is null)
 * @return
 *   The method has made a copy of the linked list starting at
 *   source.  The return value is an
 *   array where the [0] element is a head reference for the copy and the [1]
 *   element is a tail reference for the copy.
 * @exception OutOfMemoryError
 *   Indicates that there is insufficient memory for the new list.
 **/
 public static <E> Node<E>[ ] listCopyWithTail(Node<E> source)
 {
  Node<E> copyHead;
  Node<E> copyTail;
 //Node<E>[ ] answer = (Node<E>[]) new Object[2]; Causes ClassCastException!
  Node<E>[ ] answer = createArray(null, null);

  // Handle the special case of the empty list.
  if (source == null)
     return answer; // The answer has two null references .

  // Make the first node for the newly created list.
  copyHead = new Node<E>(source.data, null);
  copyTail = copyHead;

  // Make the rest of the nodes for the newly created list.
  while (source.link != null)
  {
     source = source.link;
     copyTail.addNodeAfter(source.data);
     copyTail = copyTail.link;
  }

  // Return the head and tail references.
  answer[0] = copyHead;
  answer[1] = copyTail;
  return answer;
  }


 /**
 * Compute the number of nodes in a linked list.
 * @param head
 *    the head reference for a linked list (which may be an empty list
 *   with a null head)
 * @return
 *   the number of nodes in the list with the given head
 * @note
 *   A wrong answer occurs for lists longer than Int.MAX_VALUE.
 **/
 public static <E> int listLength(Node<E> head)
 {
  Node<E> cursor;
  int answer;

  answer = 0;
  for (cursor = head; cursor != null; cursor = cursor.link)
     answer++;

  return answer;
 }


/**
* Copy part of a list, providing a head and tail reference for the new copy.
* @param start/end
*   references to two nodes of a linked list
* @param copyHead/copyTail
*   the method sets these to refer to the head and tail node of the new
*   list that is created
* @precondition
*   start and end are non-null references to nodes
*   on the same linked list,
*   with the start node at or before the end node.
* @return
*   The method has made a copy of the part of a linked list, from the
*   specified start node to the specified end node. The return value is an
*   array where the [0] component is a head reference for the copy and the
*   [1] component is a tail reference for the copy.
* @exception IllegalArgumentException
 *   Indicates that start and end do not satisfy
*   the precondition.
* @exception OutOfMemoryError
*   Indicates that there is insufficient memory for the new list.
**/
   public static <E> Node<E>[ ] listPart(Node<E> start, Node<E> end)
  {
  Node<E> copyHead;
  Node<E> copyTail;
  Node<E> cursor;
 //Node<E>[ ] answer = (Node<E>[]) new Object[2]; Causes ClassCastException!
  Node<E>[ ] answer = createArray(null, null);

  // Check for illegal null at start or end.
  if (start == null)
     throw new IllegalArgumentException("start is null");
  if (end == null)
     throw new IllegalArgumentException("end is null");

  // Make the first node for the newly created list.
  copyHead = new Node<E>(start.data, null);
  copyTail = copyHead;
  cursor = start;

  // Make the rest of the nodes for the newly created list.
  while (cursor != end)
  {
     cursor = cursor.link;
     if (cursor == null)
        throw new IllegalArgumentException
        ("end node was not found on the list");
     copyTail.addNodeAfter(cursor.data);
     copyTail = copyTail.link;
   }

   // Return the head and tail references
  answer[0] = copyHead;
   answer[1] = copyTail;
   return answer;
  }


/**
* Find a node at a specified position in a linked list.
* @param head
*   the head reference for a linked list (which may be an empty list in
*   which case the head is null)
* @param position
*   a node number
* @precondition
*   position > 0.
* @return
*   The return value is a reference to the node at the specified position in
*   the list. (The head node is position 1, the next node is position 2, and
*   so on.) If there is no such position (because the list is too short),
*   then the null reference is returned.
* @exception IllegalArgumentException
*   Indicates that position is zero.
**/
   public static <E> Node<E> listPosition(Node<E> head, int position)
   {
   Node<E> cursor;
  int i;

  if (position == 0)
       throw new IllegalArgumentException("position is zero");

  cursor = head;
  for (i = 1; (i < position) && (cursor != null); i++)
     cursor = cursor.link;

  return cursor;
  }


/**
* Search for a particular piece of data in a linked list.
* @param head
*   the head reference for a linked list (which may be an empty list in
*   which case the head is null)
* @param target
*   a target to search for
* @return
*   The return value is a reference to the first node that contains the
*   specified target. If the target is non-null, then the
*   target.equals method is used to find such a node.
*   The target may also be null, in which case the return value is a
*   reference to the first node that contains a null reference for its
*   data. If there is no node that contains the target, then the null
*   reference is returned.
**/

 public static <E> Node<E> listSearch(Node<E> head, E target)
 {
  Node<E> cursor;

  if (target == null)
  {  // Search for a node in which the data is the null reference.
     for (cursor = head; cursor != null; cursor = cursor.link)
        if (cursor.data == null)
           return cursor;
  }
  else
  {  // Search for a node that contains the non-null target.
     for (cursor = head; cursor != null; cursor = cursor.link)
        if (target.equals(cursor.data))
           return cursor;
  }

  return null;
  }


/**
* Modification method to remove the node after this node.
* @param - none
* @precondition
*   This node must not be the tail node of the list.
* @postcondition
*   The node after this node has been removed from the linked list.
*   If there were further nodes after that one, they are still
*   present on the list.
* @exception NullPointerException
*   Indicates that this was the tail node of the list, so there is nothing
*   after it to remove.
**/
public void removeNodeAfter( )
{
  link = link.link;
}


/**
* Modification method to set the data in this node.
* @param newData
*   the new data to place in this node
* @postcondition
*   The data of this node has been set to newData.
*   This data is allowed to be null.
**/
  public void setData(E newData)
  {
  data = newData;
   }


/**
* Modification method to set the link to the next node after this node.
* @param newLink
*   a reference to the node that should appear after this node in the linked
*   list (or the null reference if there is no node after this node)
* @postcondition
*   The link to the node after this node has been set to newLink.
*   Any other node (that used to be in this link) is no longer connected to
*   this node.
**/
  public void setLink(Node<E> newLink)
 {
  link = newLink;
  }



 /**
 * Create an array of Node<E> objects.  This is the only way that
* I've found to create such an array that doesn't cause a
* ClassCastException at run time.  In the textbook, I used:
*  // Node<E>[ ] answer = (Node<E>[]) new Object[2];
* but this approach now seems to fail.  I'll keep looking for
* other solutions!
**/
 private static <E> Node<E>[ ] createArray(Node<E>... nodes)
 {
  return nodes;
  }

 }

1 Ответ

0 голосов
/ 08 декабря 2018

Когда вы добавляете первый узел, связывайте его с собой.Хотя есть только один узел, он сделал бы его круговым списком.

first -> first

Затем, когда вы добавите второй узел, ваш код будет работать с узлами хранения в круговом списке.

first -> second -> first

И задним значением будет второй узел.

public void add(E item) {
    Node cursor;
    if (isEmpty( )) {
       // Insert first item.
        rear = new Node<E>(item, null);
        rear.setLink(rear);    // <=== add a link to itself to make it circular
    }
    else {
        // Insert an item that is not the first.
        rear.addNodeAfter(item);
        rear = rear.getLink( );  
    }
    manyNodes++;
}

Когда вы хотите удалитьпередний узел.Возьмите ссылку сзади (это даст вам фронт), затем установите ссылку сзади на ссылку спереди (это укажет на ссылку после передней).

первый -> второй -> третий -> первый

становится

второй -> третий -> второй

становится

третьим -> третьим

Необходимо убедиться, что в списке только один элемент.Если это произойдет, вы очистите список, установив в параметре Rear значение NULL.

public E remove() {
    if (rear == null) {
        // NoSuchElementException is from java.util and its constructor has no argument.
        throw new NoSuchElementException("Queue underflow");
    }

    E answer = rear.getLink().getData();

    if (rear.getLink() == rear) {
        // this is the last item in the list
        rear = null;
    }
    else {
        // point rear to the one after front so that front is removed
        rear.setLink(rear.getLink().getLink());
    }
    manyNodes--;
    return answer;
}

Статические методы в классе Node предполагают, что в заднем элементе есть ссылка NULL.Это не будет иметь место для круглого списка.Таким образом, эти методы будут повторять список снова и снова.Поэтому будьте осторожны, если планируете их использовать.

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