в следующем операторе выбора я хочу поставить два значения, когда @PAPCOD = 'SIN' = значения 'DD' и 'SD' и @PAPCOD = 'ENG' = значения 'DI' и 'SI'
как я могу это сделать.Только я могу поставить одно значение
SELECT ISNULL((SUM(Con_Amount)),0) +
(SELECT DISTINCT ISNULL(SUM(Correspondent_Other_Payments.Oth_Pmt_Amount),0)
FROM Correspondent_Other_Payments
WHERE Correspondent_Other_Payments.Oth_Cnt_Code = Contributions.Con_Cnt_Code and
Correspondent_Other_Payments.Oth_Prv_Code = Contributions.Con_Prv_Code and
Correspondent_Other_Payments.Oth_Dst_Code = Contributions.Con_Dst_Code and
Correspondent_Other_Payments.Oth_Cor_Code = Contributions.Con_Cor_Code and
Correspondent_Other_Payments.Oth_Pmt_Date = CONVERT(DATE, @PubDatE, 111) and
Correspondent_Other_Payments.Oth_AuditChk = 'Y')
FROM Contributions
INNER JOIN Correspondent_Master
ON Contributions.Con_Cnt_Code = Correspondent_Master.Cor_Country_Code and
Contributions.Con_Prv_Code = Correspondent_Master.Cor_Province_Code and
Contributions.Con_Dst_Code = Correspondent_Master.Cor_District_Code and
Contributions.Con_Cor_Code = Correspondent_Master.Cor_Code
WHERE Con_paper LIKE
CASE
WHEN @PapCod = 'SIN' THEN
'DD'
WHEN @PapCod = 'ENG' THEN
'DI'
ELSE
@PapCod
END and
(Con_PubDate BETWEEN CONVERT(DATE, @PubDatB, 111) and
CONVERT(DATE, @PubDatE, 111)) and
Contributions.Audit_Chk = 'Y' /* Audited */
GROUP BY Contributions.Con_Cnt_Code,
Contributions.Con_Prv_Code,
Contributions.Con_Dst_Code,
Contributions.Con_Cor_Code,
Contributions.Con_Paper
ORDER BY Contributions.Con_Cnt_Code,
Contributions.Con_Prv_Code,
Contributions.Con_Dst_Code,
Contributions.Con_Cor_Code
