Я думаю, что у меня может быть решение с использованием рекурсивных шаблонов и std :: tuple .Я скомпилировал и протестировал его, используя gcc 7.3.0.
Это заставляет меня чувствовать себя грязно, но, похоже, работает.
#include <iostream>
#include <array>
#include <tuple>
#include <type_traits>
// Forward declare A since there is a circular dependency between A and Arrays
template <size_t size, size_t start, typename... T>
struct A;
// If size is greater than start define a type that is an A::ArrayTuple from the
// next step down (size - 1) otherwise type is void
template <size_t size, size_t start, typename E, typename... T>
struct Arrays {
using type = typename std::conditional<(size > start),
typename A<size-1, start, E, T...>::ArrayTuple,
void
>::type;
};
// Use template recursion to begin at size and define std::array<int, size>
// to add to a tuple and continue marching backwards (size--) until size == start
// When size == start take all of the std::arrays and put them into a std::tuple
//
// A<size, start>::ArrayTuple will be a tuple of length (size - start + 1) where
// the first element is std::array<int, start>, the second element is
// std::array<int, start + 1> continuing until std::array<int, size>
template <size_t size, size_t start, typename... T>
struct A {
using Array = typename std::array<int, size>;
using ArrayTuple = typename std::conditional<(size == start),
typename std::tuple<Array, T...>,
typename Arrays<size, start, Array, T...>::type
>::type;
};
// This specialization is necessary to avoid infinite template recursion
template <size_t start, typename... T>
struct A<0, start, T...> {
using Array = void;
using ArrayTuple = void;
};
template <size_t size, size_t start = 1>
class Container {
public:
using ArrayTuple = typename A<size, start>::ArrayTuple;
// Shorthand way to the get type of the Nth element in ArrayTuple
template <size_t N>
using TupleElementType = typename
std::tuple_element<N-start, ArrayTuple>::type;
ArrayTuple arrays_;
// Returns a reference to the tuple element that has the type of std::array<int, N>
template <size_t N>
TupleElementType<N>& get_array() {
// Static assertion that the size of the array at the Nth element is equal to N
static_assert(std::tuple_size< TupleElementType<N> >::value == N);
return std::get<N-start>(arrays_);
}
// Prints all elements of the tuple element that has the type of std::array<int, N>
template <size_t N>
void print_array() {
auto& arr = get_array<N>();
std::cout << "Array Size: " << arr.size() << std::endl;
for (int i = 0; i < arr.size(); i++) {
std::cout << arr[i] << std::endl;
}
}
};
int main() {
// Create a new Container object where the arrays_ member will be
// a tuple with 15 elements:
// std::tuple< std::array<int, 2>, std::array<int, 3> ... std::array<int, 16> >
Container<16,2> ctr;
auto& arr2 = ctr.get_array<2>();
arr2[0] = 20;
arr2[1] = 21;
//ctr.print_array<1>(); // Compiler error since 1 < the ctr start (2)
ctr.print_array<2>(); // prints 20 and 21
ctr.print_array<3>(); // prints 3 zeros
ctr.print_array<16>(); // prints 16 zeros
//ctr.print_array<17>(); // Compiler error since 17 > the ctr size (16)
//int x(ctr.arrays_); // Compiler error - uncomment to see the type of ctr.arrays_
return 0;
}
Вот вывод из компилятора, если я раскомментирую эту строку, гдеЯ пытаюсь объявить int x
, показывающий тип ctr.arrays_
:
so.cpp: In function ‘int main()’:
so.cpp:90:22: error: cannot convert ‘Container<16, 2>::ArrayTuple {aka std::tuple<std::array<int, 2>, std::array<int, 3>, std::array<int, 4>, std::array<int, 5>, std::array<int, 6>, std::array<int, 7>, std::array<int, 8>, std::array<int, 9>, std::array<int, 10>, std::array<int, 11>, std::array<int, 12>, std::array<int, 13>, std::array<int, 14>, std::array<int, 15>, std::array<int, 16> >}’ to ‘int’ in initialization
int x(ctr.arrays_); // Compiler error - uncomment to see the type of ctr.arrays_