Почему результаты моей наиболее информативной функции для двоичной классификации всегда одинаковы в Python? - PullRequest
0 голосов
/ 18 октября 2018

Это мои полные коды для most_inforrative_feature_for_binary_classification и Naive Bayes, которые я пробовал.

def most_informative_feature_for_binary_classification(vectorizer, classifier, n=100):

        """
        Identify most important features if given a vectorizer and binary classifier. Set n to the number
        of weighted features you would like to show.
        """
        counter = 1

        def read_counter():
            return loads(open("counter.json", "r").read()) + 1 if path.exists("counter.json") else 0

        def write_counter():
            with open("counter.json", "w") as f:
                f.write(dumps(counter))

        counter = 1

        counter = read_counter()
        atexit.register(write_counter)
        if counter == 6:
            counter = 0

        # additional stopwords to be remove
        # Open a file and read it into memory
        file = open('..\stopwords.txt')
        additional_stopwords = file.read()
        additional_stopwords = additional_stopwords.split()

        class_labels = classifier.classes_
        feature_names = vectorizer.get_feature_names()
        feature_names = [word for word in feature_names if word not in additional_stopwords]

        topn_class1 = sorted(zip(classifier.coef_[0], feature_names))[:n]
        topn_class2 = sorted(zip(classifier.coef_[0], feature_names))[-n:]

        # class_labels = category
        # coef = co-effecient
        # feat = most informative feature
        if counter == 1:
            for coef, feat in topn_class1:
                print(class_labels[0], coef, feat)
                print(class_labels)

            print()

            for coef, feat in reversed(topn_class2):
                print(class_labels[1], coef, feat)

        elif counter == 2:
            for coef, feat in topn_class1:
                print(class_labels[1], coef, feat)

            print()

            for coef, feat in reversed(topn_class2):
                print(class_labels[2], coef, feat)

        elif counter == 3:
            for coef, feat in topn_class1:
                print(class_labels[2], coef, feat)

            print()

            for coef, feat in reversed(topn_class2):
                print(class_labels[3], coef, feat)

        elif counter == 4:
            for coef, feat in topn_class1:
                print(class_labels[3], coef, feat)

            print()

            for coef, feat in reversed(topn_class2):
                print(class_labels[4], coef, feat)

        elif counter == 5:
            for coef, feat in topn_class1:
                print(class_labels[4], coef, feat)

            print()

            for coef, feat in reversed(topn_class2):
                print(class_labels[5], coef, feat)

        else:
            print("=== PLEASE RUN PROGRAM AGAIN TO VIEW THE CO-EFFICIENT FOR THE CHOSEN MODEL ===")


    '''=========================================================================================='''
    '''MEAN ACCURACY FOR 4 MODELS(NAIVE BAYES / LOGISTICS REGRESSION / LINEAR SVC / RANDOM FOREST)'''
    '''=========================================================================================='''
    # n_estimators is the number of trees to be used in the fores
    def mean_acc():
        models = [
            RandomForestClassifier(n_estimators=200, max_depth=3, random_state=0),
            LinearSVC(),
            MultinomialNB(),
            LogisticRegression(random_state=0)]
        CV = 6
        cv_df = pd.DataFrame(index=range(CV * len(models)))
        entries = []
        for model in models:
            model_name = model.__class__.__name__
            accuracies = cross_val_score(model, features, labels, scoring='accuracy', cv=CV)
            for fold_idx, accuracy in enumerate(accuracies):
                entries.append((model_name, fold_idx, accuracy))
        cv_df = pd.DataFrame(entries, columns=['model_name', 'fold_idx', 'accuracy'])

        print(cv_df.groupby('model_name').accuracy.mean())


    '''=========================================================================================='''
    '''NAIVE BAYES CLASSIFIER'''
    '''=========================================================================================='''


    def NB_func():
        X_train, X_test, y_train, y_test = train_test_split(df['content'], df['cat_id'], random_state=0)
        count_vect = CountVectorizer()
        X_train_counts = count_vect.fit_transform(X_train)
        tfidf_transformer = TfidfTransformer()
        X_train_tfidf = tfidf_transformer.fit_transform(X_train_counts)
        clf_NB = MultinomialNB().fit(X_train_tfidf, y_train)
        print(clf_NB)

        # save the model to disk
        filename = '../dataanalysis/models/Naive_Bayes.sav'
        pickle.dump(clf_NB, open(filename, 'wb'))

        print()
        '''Print the prediction of the category from the unknown document'''
        # For now its not accurate due to insufficient sample data
        # print("NAIVE BAYES CLASSIFIER: ", clf_NB.predict(count_vect.transform([""])))
        print()

        print("===============================================")
        print("================= NAIVE BAYES =================")
        print("===============================================")
        most_informative_feature_for_binary_classification(tfidf, clf_NB, n=10)

Вывод при запуске NB_func ():

При первом запуске программы:

3 -7.730506816516725 abato
3 -7.730506816516725 abdome abdome
3 -7.730506816516725 abdome erythema
3 -7.730506816516725 abdome erythema redness
3 -7.730506816516725 abdomen distended complaint
3 -7.730506816516725 abdomen ex drain
3 -7.730506816516725 abdomen hbs
3 -7.730506816516725 abdomen hbs kidneys
3 -7.730506816516725 abdomen insitu
3 -7.730506816516725 abdomen insitu pinkish

4 -7.254153151633855 assist function toileting
4 -7.331276619904304 bnoxl
4 -7.343069108877106 assist incontinence
4 -7.384156232690568 breath utcome ineffective
4 -7.387014055512514 arora plansfollow
4 -7.4053139680029565 agitated change
4 -7.410079385200252 ambulate using aid
4 -7.443599738543319 accompanied bedside complain
4 -7.44802940166431 alert comfortable afebrile
4 -7.455925447446086 absence urinary symptoms

Второй раз при запуске программы:

 4 -7.730945941543211 abato
 4 -7.730945941543211 abdome abdome
 4 -7.730945941543211 abdome erythema
 4 -7.730945941543211 abdome erythema redness
 4 -7.730945941543211 abdomen distended complaint
 4 -7.730945941543211 abdomen ex drain
 4 -7.730945941543211 abdomen hbs
 4 -7.730945941543211 abdomen hbs kidneys
 4 -7.730945941543211 abdomen insitu
 4 -7.730945941543211 abdomen insitu pinkish

5 -7.254592276660341 assist function toileting
5 -7.331715744930789 bnoxl discharge previously
5 -7.3435082339035915 assist incontinence
5 -7.384595357717053 breathing
5 -7.387453180539 arora
5 -7.405753093029442 agitated change
5 -7.410518510226737 ambulate using
5 -7.444038863569804 accompanied bedside complain
5 -7.448468526690795 alert comfortable
5 -7.456364572472571 absence urinary symptoms

В третий раз запустить программу:

5 -7.730506816516725 abato
5 -7.730506816516725 abdome abdome
5 -7.730506816516725 abdome erythema
5 -7.730506816516725 abdome erythema redness
5 -7.730506816516725 abdomen distended complaint
5 -7.730506816516725 abdomen ex drain
5 -7.730506816516725 abdomen hbs
5 -7.730506816516725 abdomen hbs kidneys
5 -7.730506816516725 abdomen insitu
5 -7.730506816516725 abdomen insitu pinkish

6 -7.254153151633855 assist incontinence urine
6 -7.331276619904304 board
6 -7.343069108877106 assist indwelling
6 -7.384156232690568 breathing
6 -7.387014055512514 arora plansfollow watch
6 -7.4053139680029565 agitated change
6 -7.410079385200252 ambulate using aid
6 -7.443599738543319 accompanied bedside complain
6 -7.44802940166431 alert comfortable afebrile
6 -7.455925447446086 absence urinary symptoms

В четвертый раз запустить программу:

6 -7.730492001996121 abato
6 -7.730492001996121 abdome abdome
6 -7.730492001996121 abdome erythema
6 -7.730492001996121 abdome erythema redness
6 -7.730492001996121 abdomen distended complaint
6 -7.730492001996121 abdomen ex drain
6 -7.730492001996121 abdomen hbs
6 -7.730492001996121 abdomen hbs kidneys
6 -7.730492001996121 abdomen insitu
6 -7.730492001996121 abdomen insitu pinkish

7 -7.25347933696348 assist incontinence urine
7 -7.3312618053837 board
7 -7.342671383051713 assist indwelling
7 -7.383811392545885 breathing decreased shortness
7 -7.3865695243404845 arora plansfollow watch
7 -7.405088464279118 agitated behaviour aggression
7 -7.4098105414391995 ambulating
7 -7.443278461891396 accompanied bedside
7 -7.4477507335224775 alert conscious
7 -7.455910632925482 absence urinary

Пятый раз запустить программу:

7 -7.730945941543211 abato
7 -7.730945941543211 abdome abdome
7 -7.730945941543211 abdome erythema
7 -7.730945941543211 abdome erythema redness
7 -7.730945941543211 abdomen distended complaint
7 -7.730945941543211 abdomen ex drain
7 -7.730945941543211 abdomen hbs
7 -7.730945941543211 abdomen hbs kidneys
7 -7.730945941543211 abdomen insitu
7 -7.730945941543211 abdomen insitu pinkish

8 -7.254592276660341 assist incontinence urine
8 -7.331715744930789 board reassessment indicated
8 -7.3435082339035915 assist indwelling
8 -7.384595357717053 breathing free respiratory
8 -7.387453180539 aroun
8 -7.405753093029442 agitated behaviour aggression
8 -7.410518510226737 ambulate prior admission
8 -7.444038863569804 accompanied bedside
8 -7.448468526690795 alert afebrile complains
8 -7.456364572472571 absence urinary

Проблема, с которой я столкнулся, заключается в том, почему я всегда получаю одинаковые результаты при каждом запуске своей программы.Классы имеют одинаковые результаты вместо другого.

Добро пожаловать на сайт PullRequest, где вы можете задавать вопросы и получать ответы от других членов сообщества.
...