Функция MySQL с несколькими счетами и суммами, возвращающая неправильные значения с несколькими объединениями в результате MySQL

Question

Таблица mpkids_students AS A

id      BranchId    Email                   Mobile      StudentId
9497    25          mpsuraj2016@gmail.com   8700698773  25
9498    25          m016@gmail.com          8700698776  26

Таблица mpkids_student_image_gallery AS B

id      like_count  student_id
1       25          27

Таблица mpkids_visitors AS C

id      student_id
1       9497
2       9497
3       9497

Таблица mpkids_visitors_count AS D

id  visitor_count   student_id
1   4               23

Таблица mpkids_image_likes AS E

id  student_id
1   67

Таблица mpkids_relatives_data AS F

id  student_id  rel_email               rel_mobile
1   9497        kushwahji@gmail.com     9009859691
2   9497        kushwah@gmail.com       7566403326
3   9497        kushwah@gmail.com       1236403326
4   9497        suraj@gmail.com         123640332

Таблица mpkids_paidstatus AS G

id  student_id  Received
1   9497        7500
2   9497        3000
3   9497        3000

MYSQL QUERY

SELECT A.id as student_id,
COUNT(DISTINCT B.id) as images, 
COUNT(DISTINCT C.id)+ COUNT(DISTINCT D.visitor_count)  as visits, 
count(DISTINCT E.id) + SUM(B.like_count) as likes, 
COUNT(DISTINCT A.Email)+COUNT(DISTINCT F.rel_email)  as emails, 
COUNT(DISTINCT A.Mobile)+COUNT(DISTINCT F.rel_mobile)  as moibles, 
SUM(G.Received)  as Received 
FROM mpkids_students AS A 
LEFT JOIN mpkids_student_image_gallery AS B ON B.student_id = A.id 
LEFT JOIN mpkids_visitors AS C ON C.student_id = A.id 
LEFT JOIN mpkids_visitors_count AS D ON D.student_id = A.id 
LEFT JOIN mpkids_image_likes AS E ON E.student_id = A.id 
LEFT JOIN mpkids_relatives_data AS F ON F.student_id = A.id 
LEFT JOIN mpkids_paidstatus AS G ON G.student_id = A.id 
WHERE A.BranchId = 25 
GROUP BY A.id 
ORDER BY A.StudentId DESC

Результат:

student_id  images  visits  likes   emails  moibles Received    
9497        0       3       NULL    4       5       202500  
9498        0       0       NULL    1       1       NULL    

Неисправность Объяснение:

Полученное поле возвращает неправильное значениеЯ пробовал много запросов, но не получил решение. Полученное поле правильное значение 13500 для student_id = 9497 Пожалуйста, помогите мне найти решение.

Answer 1

Вы получаете неправильный вывод, потому что, когда вы присоединяетесь на основе студента, вы получаете несколько записей из таблицы mpkids_paidstatus для каждого учащегося, которая суммирует и возвращает неправильный вывод.

Вы можететакже напишите ваш запрос, как показано ниже, используя подзапрос.

SELECT A.id as student_id,
COUNT(DISTINCT B.id) as images, 
COUNT(DISTINCT C.id)+ COUNT(DISTINCT D.visitor_count)  as visits, 
count(DISTINCT E.id) + SUM(B.like_count) as likes, 
COUNT(DISTINCT A.Email)+COUNT(DISTINCT F.rel_email)  as emails, 
COUNT(DISTINCT A.Mobile)+COUNT(DISTINCT F.rel_mobile)  as moibles, 
(select SUM(Received) from mpkids_paidstatus ps where ps.student_id=a.id)  as Received 
FROM mpkids_students AS A 
LEFT JOIN mpkids_student_image_gallery AS B ON B.student_id = A.id 
LEFT JOIN mpkids_visitors AS C ON C.student_id = A.id 
LEFT JOIN mpkids_visitors_count AS D ON D.student_id = A.id 
LEFT JOIN mpkids_image_likes AS E ON E.student_id = A.id 
LEFT JOIN mpkids_relatives_data AS F ON F.student_id = A.id 

WHERE A.BranchId = 25 
GROUP BY A.id 
ORDER BY A.StudentId DESC