Получение ошибок, таких как «cursor.execute», не допускается, и cursor.fetchall () не принимает аргументов (2 govem)

Question

Я делаю программу Python SQL для проекта, и у меня возникают проблемы с ошибками входа в систему.Вот весь раздел входа в систему

print("Welcome to the program")
    while True:
        print("If this is your first time playing, you may create an account. If not, log in to an existing one. login/create. If you'd like to exit, type in exit.")
        answer = input()
        if answer == 'login':
            while True:
                db = sqlite3.connect('data/users')
                cursor.execute('''
                        CREATE TABLE IF NOT EXISTS users(id INTEGER PRIMARY KEY, username TEXT,
                                        password TEXT, score TEXT)
                        ''')
                username = input("Insert username")
                password = input("Insert password")
                id = cursor.lastrowid
                user_search = cursor.fetchall('''SELECT * FROM users WHERE id = 1 AND username = ? AND password = ?''', (username, password))
                cursor.execute(user_search[(username),(password)])
                data=cursor.fetchall()
                if data is None:
                    print("Nothing found with an id of 1, nor are there matchign results for the username and password.")
                else:
                    print("None found.")
                    #/1769450/kak-proverit-nalichie-stroki-v-sqlite-s-python Code reference, this site helped me find out what I was doing wrong
        elif answer == 'create':
            print("You may create an account if there are none.")
            username = input("Create a new username. Case sensitive.")
            password = input("Create a new password. Case sensitive.")
            user_search = cursor.execute('''SELECT * FROM users WHERE id = 1 AND username = ? AND password = ?''', (username, password))
            result = cursor.fetchall()
            cursor.execute(user_search[(username),(password)])
            if result:
                for i in result:
                    print("There is only one user slot allowed. Said slot is taken. You may not create an account.")
                    break
            else:
                print("User slot free. Appending credentials. You have created an account.")
                credentials =[(username),(password)]
                cursor.executemany('''INSERT INTO users(username, password) VALUES(?,?)''', (users))

        else:
            print("Input not recognised.")

В частности, этот раздел:

 username = input("Insert username")
            password = input("Insert password")
            id = cursor.lastrowid
            user_search = cursor.fetchall('''SELECT * FROM users WHERE id = 1 AND username = ? AND password = ?''', (username, password))
            cursor.execute(user_search[(username),(password)])
            data=cursor.fetchall()
            if data is None:
                print("Nothing found with an id of 1, nor are there matching results for the username and password.")
            else:
                print("None found.")

Я не привык к написанию кода на python, поэтому я не знаю, почему я получаю этиошибки.SQL довольно новый для меня тоже.Я получаю сообщение «fetchall принимает 0 аргументов, 2 дано», и мне не удалось найти жизнеспособное решение

Answer 1

fetchall() не принимает аргументы и предназначен для извлечения результата запроса.Сначала execute запрос, а затем выборка.

username = input("Insert username")
password = input("Insert password")
id = cursor.lastrowid    
cursor.execute('''SELECT * FROM users WHERE id = %s AND username = %s
                                AND password = %s''' % (id, username, password))
data = cursor.fetchall()