Это мои попытки сделать SELECT из трех таблиц.Но они не компилируются, и я не понимаю ошибку (я не знаю, почему она ожидает кортеж (Entity Issue, b0)
вместо триплета, который, я думаю, пытается получить код).
Попытка 1:
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
module Handler.Support where
import Import hiding ((==.))
import qualified Database.Esqueleto as E
import Database.Esqueleto ((^.), (==.), (&&.))
import Data.Traversable
getSupportR :: CustomerId -> Handler Html
getSupportR customerId = do
customer_issues_followUps_list <- runDB $
E.select $
E.from $ \(i, f, c) -> do
E.where_ (i ^. IssueCustomerId ==. E.val customerId &&. i ^. IssueId ==. f ^. FollowUpIssueId &&. i ^. IssueCustomerId ==. c ^. CustomerId)
return (i, f, c)
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
defaultLayout $ do
setTitle "Your Licenses"
$(widgetFile "support-display")
ошибка 1:
/home/hhefesto/dev/laurus-nobilis/src/Handler/Support.hs:41:5: error:
• Couldn't match type ‘(ra, rb, rc)’ with ‘(Entity Issue, b0)’
arising from a functional dependency between:
constraint ‘Database.Esqueleto.Internal.Sql.SqlSelect
(E.SqlExpr (Entity Issue), E.SqlExpr (Entity FollowUp),
E.SqlExpr (Entity Customer))
(Entity Issue, b0)’
arising from a use of ‘E.select’
instance ‘Database.Esqueleto.Internal.Sql.SqlSelect
(a3, b3, c) (ra3, rb3, rc3)’
at <no location info>
• In the second argument of ‘($)’, namely
‘E.select
$ E.from
$ \ (i, f, c)
-> do E.where_
(i ^. IssueCustomerId ==. E.val customerId
&&.
i ^. IssueId ==. f ^. FollowUpIssueId
&&. i ^. IssueCustomerId ==. c ^. CustomerId)
return (i, f, c)’
In a stmt of a 'do' block:
customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i, f, c)
-> do E.where_
(i ^. IssueCustomerId
==. E.val customerId
&&.
i ^. IssueId
==. f ^. FollowUpIssueId
&&.
i ^. IssueCustomerId
==. c ^. CustomerId)
return (i, f, c)
In the expression:
do customer_issues_followUps_list <- runDB
$ E.select $ E.from $ \ (i, f, c) -> do ...
let issues
= map listToMaybe . group . sort . fst . unzip
$ customer_issues_followUps_list
defaultLayout
$ do setTitle "Your Licenses"
(do ...)
|
41 | E.select $
| ^^^^^^^^^^...
Попытка 2:
{-# LANGUAGE ScopedTypeVariables #-}
{-# LANGUAGE NoImplicitPrelude #-}
{-# LANGUAGE OverloadedStrings #-}
{-# LANGUAGE TemplateHaskell #-}
{-# LANGUAGE MultiParamTypeClasses #-}
{-# LANGUAGE TypeFamilies #-}
module Handler.Support where
import Import hiding ((==.))
import qualified Database.Esqueleto as E
import Database.Esqueleto ((^.), (==.), (&&.))
import Data.Traversable
getSupportR :: CustomerId -> Handler Html
getSupportR customerId = do
customer_issues_followUps_list <- runDB $
E.select $
E.from $ \(i `E.InnerJoin` f `E.InnerJoin` c) -> do
E.on (c ^. CustomerId ==. i ^. IssueCustomerId)
E.on (i ^. IssueId ==. f ^. FollowUpIssueId)
E.where_ (i ^. IssueCustomerId ==. E.val customerId)
return (i, f, c)
let issues = map listToMaybe . group . sort . fst . unzip $ customer_issues_followUps_list
defaultLayout $ do
setTitle "Your Licenses"
$(widgetFile "support-display")
Ошибка 2:
/home/hhefesto/dev/laurus-nobilis/src/Handler/Support.hs:40:5: error:
• Couldn't match type ‘(ra, rb, rc)’ with ‘(Entity Issue, b0)’
arising from a functional dependency between:
constraint ‘Database.Esqueleto.Internal.Sql.SqlSelect
(E.SqlExpr (Entity Issue), E.SqlExpr (Entity FollowUp),
E.SqlExpr (Entity Customer))
(Entity Issue, b0)’
arising from a use of ‘E.select’
instance ‘Database.Esqueleto.Internal.Sql.SqlSelect
(a2, b2, c) (ra2, rb2, rc2)’
at <no location info>
• In the second argument of ‘($)’, namely
‘E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do E.on (c ^. CustomerId ==. i ^. IssueCustomerId)
E.on (i ^. IssueId ==. f ^. FollowUpIssueId)
....’
In a stmt of a 'do' block:
customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do E.on
(c ^. CustomerId
==. i ^. IssueCustomerId)
E.on
(i ^. IssueId
==. f ^. FollowUpIssueId)
....
In the expression:
do customer_issues_followUps_list <- runDB
$ E.select
$ E.from
$ \ (i `E.InnerJoin` f `E.InnerJoin` c)
-> do ...
let issues
= map listToMaybe . group . sort . fst . unzip
$ customer_issues_followUps_list
defaultLayout
$ do setTitle "Your Licenses"
(do ...)
|
40 | E.select $
| ^^^^^^^^^^...
это моя постоянная модель:
Customer
email Text
password Text
firstName Text
lastName Text
address1 Text
address2 Text
city Text
state Text
zipCode Text
country Text
phone Text
organization Text
UniqueCustomer email
deriving Typeable
deriving Show
deriving Eq
deriving Ord
License
licenseAlias Text
expirationDate UTCTime
assignedTo CustomerId
customerId CustomerId
deriving Show
deriving Eq
deriving Ord
Issue
customerId CustomerId
issueSummary Text
issueDetails Text
issueState Int
issueDate UTCTime
deriving Show
deriving Eq
deriving Ord
FollowUp
issueId IssueId
followUpDate UTCTime
followUpAuthor CustomerId
followUpText Text
deriving Show
deriving Eq
deriving Ord
-- Soon to be deleted:
Email
email Text
customerId CustomerId Maybe
verkey Text Maybe
UniqueEmail email
Comment json -- Adding "json" causes ToJSON and FromJSON instances to be derived.
message Text
customerId CustomerId Maybe
deriving Eq
deriving Show
Как видите, ошибка в обеих попытках одинакова: ожидался кортеж вместо триплета.
Любая помощь будет принята с благодарностью:)