Попробуйте, используя split(',')
в качестве первого элемента в list of list
, равном string
, разделенном comma
.
>>> lst = [['Afghanistan,2.66171813,7.460143566,0.490880072,52.33952713,0.427010864,-0.106340349,0.261178523'], ['Albania,4.639548302,9.373718262,0.637698293,69.05165863,0.74961102,-0.035140377,0.457737535']]
Вывод:
>>> [el[0].split(',')[0] for el in lst]
['Afghanistan', 'Albania']
Объяснение:
# el[0] gives the first element in you list which a string.
# .split(',') returns a list of elements after spliting by `,`
# [0] finally selecting your first element as required.
Правка-1:
Использование regex
,
pattern = r'([a-zA-Z]+)'
new_lst = []
for el in lst:
new_lst+=re.findall(pattern, el[0])
>>> new_lst # output
['Afghanistan', 'Albania']