Самый питонский способ сделать это, используя списки и функцию отображения
nlist = [[240, 10, 10, 10, 10, 10, 10, 240],
[80, 80, 240, 80, 80, 240, 80, 80],
[80, 80, 240, 80, 80, 240, 80, 80],
[80, 80, 150, 150, 150, 150, 80, 80],
[80, 80, 240, 240, 240, 240, 80, 80],
[80, 80, 150, 150, 150, 150, 80, 80],
[240, 240, 150, 150, 150, 150, 240, 240],
[240, 240, 150, 150, 150, 150, 240, 240]]
nlist[:] = [list(map(lambda x: x*1.1 if x*1.1<=255 else 'BURN OUT',sub_list)) for sub_list in nlist]
Вывод:
[['BURN OUT', 11.0, 11.0, 11.0, 11.0, 11.0, 11.0, 'BURN OUT'],
[88.0, 88.0, 'BURN OUT', 88.0, 88.0, 'BURN OUT', 88.0, 88.0],
[88.0, 88.0, 'BURN OUT', 88.0, 88.0, 'BURN OUT', 88.0, 88.0],
[88.0, 88.0, 165.0, 165.0, 165.0, 165.0, 88.0, 88.0],
[88.0, 88.0, 'BURN OUT', 'BURN OUT', 'BURN OUT', 'BURN OUT', 88.0, 88.0],
[88.0, 88.0, 165.0, 165.0, 165.0, 165.0, 88.0, 88.0],
['BURN OUT', 'BURN OUT', 165.0, 165.0, 165.0, 165.0, 'BURN OUT', 'BURN OUT'],
['BURN OUT', 'BURN OUT', 165.0, 165.0, 165.0, 165.0, 'BURN OUT', 'BURN OUT']]