Почему мой код заканчивается, хотя я добавляю способ перезапустить его

Question

Здравствуйте, это я снова спрашиваю о своем коде. Я создаю Rock, Paper, Scissor, добавляю main() и def main(): и делаю отступ, но когда я запускаю код, это происходит

C:\Users\Timothy\Documents>python text.py

C:\Users\Timothy\Documents>

это мой код

def main():
    import random
    print("1=Rock, 2=Paper, 3=Scissor")
    player = int(input("Please Put your choice"))
    ai = random.randint(1,3)
        ###if and else statement for ai to print the random integer to string
    if (ai == 3):
        print("AI: Scissor")
    elif (ai == 2):
        print("AI: Paper")
    elif (ai == 1):
        print("AI: Rock")
            ####if and statement for the ai and player
    if (player == ai):
        print("It is a tie")
    if (player == 1 and ai == 2):
        print("AI won")
    if (player == 1 and ai == 3):
         print("You Won!!")
    if (player == 2 and ai == 1):
        print("You won")
    if (player == 2 and ai == 3):
        print("AI won")
    if (player == 3 and ai == 1):
        print("AI won")
    if (player == 3 and ai == 2):
        print("You won")

        main()

Answer 1

Да слишком много отступов

def main():
    import random
    print("1=Rock, 2=Paper, 3=Scissor")
    player = int(input("Please Put your choice"))
    ai = random.randint(1,3)
        ###if and else statement for ai to print the random integer to string
    if (ai == 3):
        print("AI: Scissor")
    elif (ai == 2):
        print("AI: Paper")
    elif (ai == 1):
        print("AI: Rock")
            ####if and statement for the ai and player
    if (player == ai):
        print("It is a tie")
    if (player == 1 and ai == 2):
        print("AI won")
    if (player == 1 and ai == 3):
         print("You Won!!")
    if (player == 2 and ai == 1):
        print("You won")
    if (player == 2 and ai == 3):
        print("AI won")
    if (player == 3 and ai == 1):
        print("AI won")
    if (player == 3 and ai == 2):
        print("You won")

        main() # this way if will run if this condition is met player == 3 and ai == 2
    main() # this will surely run in the end calling itself

Answer 2

Вот способ зациклить программу, используя while True, так что в игру можно играть более одного раза.

def main():
    import random
    print("1=Rock, 2=Paper, 3=Scissor")
    player = int(input("Please Put your choice"))
    ai = random.randint(1,3)
        ###if and else statement for ai to print the random integer to string
    if (ai == 3):
        print("AI: Scissor")
    elif (ai == 2):
        print("AI: Paper")
    elif (ai == 1):
        print("AI: Rock")
            ####if and statement for the ai and player
    if (player == ai):
        print("It is a tie")
    if (player == 1 and ai == 2):
        print("AI won")
    if (player == 1 and ai == 3):
         print("You Won!!")
    if (player == 2 and ai == 1):
        print("You won")
    if (player == 2 and ai == 3):
        print("AI won")
    if (player == 3 and ai == 1):
        print("AI won")
    if (player == 3 and ai == 2):
        print("You won")


while True:
    main()
    restart = input("Again? Y/N: ").upper()
    if restart == "Y":
        main()
    if restart == "N":
        break