Я не могу понять, как это сделать в kotlin. Я хочу преобразовать эту строку в массив объектов:
[
{mode=bus, line=381, line_name=381, direction=Waterloo, operator=CX, date=2019-10-16, expected_departure_date=2019-10-16, aimed_departure_time=20:11, expected_departure_time=20:13, best_departure_estimate=20:13, source=Countdown instant, dir=outbound, operator_name=ABELLIO LONDON LIMITED, id=https://transportapi.com/v3/uk/bus/route/CX/381/outbound/490010596E/2019-10-16/20:11/timetable.json?app_id=f56baf6a&app_key=6b0d065a1465ccbb6f32438f3d960803},
{mode=bus, line=381, line_name=381, direction=Waterloo, operator=CX, date=2019-10-16, expected_departure_date=2019-10-16, aimed_departure_time=20:33, expected_departure_time=20:34, best_departure_estimate=20:34, source=Countdown instant, dir=outbound, operator_name=ABELLIO LONDON LIMITED, id=https://transportapi.com/v3/uk/bus/route/CX/381/outbound/490010596E/2019-10-16/20:33/timetable.json?app_id=f56baf6a&app_key=6b0d065a1465ccbb6f32438f3d960803}
]
Объект, который я тоже хочу преобразовать:
@JsonClass(generateAdapter = true)
data class BusLive(val aimed_departure_time: String, val best_departure_estimate: String, val date: String, val dir: String,
val direction: String,
val expected_departure_date: String,
val expected_departure_time: String,
val id: String,
val line: String,
val line_name: String,
val mode: String,
val operator: String,
val operator_name: String,
val source: String
)
Я пробовал:
fun moshiConverter(test:String) : String {
val moshi = Moshi.Builder().build()
val type = Types.newParameterizedType(LiveBus::class.java, LiveBus::class.java)
val adapter:JsonAdapter<String> = moshi.adapter(type)
val a = adapter.toJson(test)
return a
}
И без радости: (