Набор запросов SELF JOIN для объединенной таблицы в Django? - PullRequest
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Набор запросов SELF JOIN для объединенной таблицы в Django?

1 голос
/ 31 октября 2019

Я хочу сделать самостоятельное соединение для объединенной таблицы.

У меня есть набор запросов: 

paymentsss = Transaction.objects.all().select_related('currency',
     'payment_source__payment_type','deal__service',
          'deal__service__contractor').order_by('-id')

, который преобразуется в: 

 SELECT "processing"."transaction"."id", 
       "processing"."transaction"."currency_id", 
       "processing"."transaction"."deal_id", 
       "processing"."transaction"."payment_source_id", 
       "processing"."transaction"."payment_date", 
       "processing"."transaction"."amount", 
       "processing"."transaction"."status", 
       "processing"."transaction"."context", 
       "processing"."currency"."id", 
       "processing"."currency"."iso_name", 
       "processing"."currency"."minor_unit", 
       "processing"."deal"."id", 
       "processing"."deal"."service_id", 
       "processing"."deal"."currency_id",
       "processing"."service"."id",
       "processing"."service"."contractor_id",
       "processing"."service"."name", 
       "processing"."service"."description", 
       "processing"."contractor"."id", 
       "processing"."contractor"."name", 
       "processing"."payer_payment_source"."id", 
       "processing"."payer_payment_source"."payment_type_id", 
       "processing"."payer_payment_source"."source_details", 
       "processing"."payment_type"."id", 
       "processing"."payment_type"."name" 
  FROM "processing"."transaction" 
  LEFT OUTER JOIN "processing"."currency" 
    ON ("processing"."transaction"."currency_id" = "processing"."currency"."id") 
  LEFT OUTER JOIN "processing"."deal" 
    ON ("processing"."transaction"."deal_id" = "processing"."deal"."id") 
  LEFT OUTER JOIN "processing"."service" 
    ON ("processing"."deal"."service_id" = "processing"."service"."id") 
  LEFT OUTER JOIN "processing"."contractor" 
    ON ("processing"."service"."contractor_id" = "processing"."contractor"."id") 
  LEFT OUTER JOIN "processing"."payer_payment_source" 
    ON ("processing"."transaction"."payment_source_id" = "processing"."payer_payment_source"."id") 
  LEFT OUTER JOIN "processing"."payment_type" 
    ON ("processing"."payer_payment_source"."payment_type_id" = "processing"."payment_type"."id")

Этофрагмент из таблицы payment_source. Поля, содержащие bank_card, объединены с Transaction, но bank_card_details нет. У них одинаковые payer_id. Необходимо, чтобы эти две строки были объединены в одну. Как я могу это сделать?

enter image description here

Models.py 

class Transaction(models.Model):
    id = models.BigIntegerField(blank=True, null=False, primary_key=True)
    currency = models.ForeignKey(Currency, null=True, on_delete=models.CASCADE)
    deal = models.ForeignKey(Deal, null=True, on_delete=models.CASCADE)
    # service_instance = models.ForeignKey(ServiceInstance, null=True, on_delete=models.CASCADE)
    payment_source = models.ForeignKey(PayerPaymentSource, null=True, on_delete=models.CASCADE)
    payment_date = models.DateTimeField(blank=True, null=True)
    amount = models.IntegerField(blank=True, null=True)
    status = models.CharField(max_length=255, blank=True, null=True)
    context = models.TextField(blank=True, null=True)

    class Meta:
        managed = False
        db_table = '"processing"."transaction"'

class PayerPaymentSource(models.Model):
    id = models.BigIntegerField(blank=True, null=False, primary_key=True)
    # payer_id = models.BigIntegerField(blank=True, null=True)
    payment_type = models.ForeignKey(PaymentType, max_length=64, blank=True, null=True, on_delete=models.CASCADE)
    source_details = models.TextField(blank=True, null=True)  # This field type is a guess.

    class Meta:
        managed = False
        db_table = '"processing"."payer_payment_source"'

UPD: основано на наборе запросов django, Iизменил запрос, чтобы он соответствовал моим целям (затронуты только последние 3 строки). Как передать его в Django ORM? Мне это нужно, потому что в Django ORM удобные фильтры для поиска. 

 SELECT "processing"."transaction"."id",
       "processing"."transaction"."currency_id",
       "processing"."transaction"."deal_id",
       "processing"."transaction"."payment_source_id",
       "processing"."transaction"."payment_date",
       "processing"."transaction"."amount",
       "processing"."transaction"."status",
       "processing"."transaction"."context",
       "processing"."currency"."id",
       "processing"."currency"."iso_name",
       "processing"."currency"."minor_unit",
       "processing"."deal"."id",
       "processing"."deal"."service_id",
       "processing"."deal"."currency_id",
       "processing"."service"."id",
       "processing"."service"."contractor_id",
       "processing"."service"."name",
       "processing"."service"."description",
       "processing"."contractor"."id",
       "processing"."contractor"."name",
       "ps"."id",
       "ps"."payment_type_id",
       "ps"."source_details",
       "processing"."payment_type"."id",
       "processing"."payment_type"."name",
       "psc"."source_details"
FROM "processing"."transaction"
LEFT OUTER JOIN "processing"."currency" ON ("processing"."transaction"."currency_id" = "processing"."currency"."id")
LEFT OUTER JOIN "processing"."deal" ON ("processing"."transaction"."deal_id" = "processing"."deal"."id")
LEFT OUTER JOIN "processing"."service" ON ("processing"."deal"."service_id" = "processing"."service"."id")
LEFT OUTER JOIN "processing"."contractor" ON ("processing"."service"."contractor_id" = "processing"."contractor"."id")
LEFT OUTER JOIN "processing"."payer_payment_source" AS "ps" ON ("processing"."transaction"."payment_source_id" = "ps"."id")
LEFT OUTER JOIN "processing"."payment_type" ON ("ps"."payment_type_id" = "processing"."payment_type"."id")
LEFT OUTER JOIN "processing"."payer_payment_source" AS "psc" ON ("ps"."payer_id" = "psc"."payer_id") AND "psc"."payment_type_id" = 'bank_card_details'
...