У меня есть библиотека C ++ (на самом деле обертка для другой библиотеки C ++), и мне нужно передать struct
s моему приложению C.
Я не знаю, как динамически распределять память.
Я получаю ошибку сегментации.
library.h
struct my_substruct {
unsigned char id ;
time_t date ;
char *info ;
};
typedef struct my_substruct My_substruct ;
struct my_struct {
char *description ;
unsigned char value ;
My_substruct *substruct ;
};
typedef my_struct My_struct ;
library.cpp
unsigned char getStructs(My_struct *structs)
{
vector <structCPPLibrary> structsCPPLibrary = getFromCPPLibrary();
unsigned char numStructs = structsCPPLibrary.size();
structs = (My_struct *)malloc(numStructs*sizeof(My_struct));
unsigned char indexStruct = 0;
for (auto s : structsCPPLibrary)
{
structs[indexStruct].description = (char *)malloc(s.description.size() + 1);
strcpy(structs[indexStruct].description, s.description.c_str()); // In 's' is a std::string
structs[indexStruct].value = s.value; // In 's' is an unsigned char too
unsigned char numSubstructs = s.substructs.size(); // In 's' is a vector of Substructs
structs[indexStruct].substruct = (My_substruct *)malloc(numSubstructs*sizeof(My_substruct));
unsigned char indexSubstruct = 0;
for (auto sub : s.substruct) {
structs[indexStruct].substruct[indexSubstruct].id = sub.id; // In 'sub' is an unsigned char too
structs[indexStruct].substruct[indexSubstruct].date = sub.date; // In 'sub' is a time_t too
structs[indexStruct].substruct[indexSubstruct].info = (char *)malloc(sub.info.size() + 1);
strcpy(structs[indexStruct].substruct[indexSubstruct].info, sub.info.c_str()); // In 'sub' is a std::string
indexSubstruct++;
}
indexStruct++;
}
return indexStruct;
}
main.c
void getStructFromWrapper(void)
{
My_struct *structs;
unsigned char numStruct = getStructs(structs);
show_content(structs);
}