Как сделать графический интерфейс для игры на линкоре Python

Question

Итак, для школьного проекта мне нужно сделать игру на линкоре на python, которая требует графического интерфейса. Мне поручили использовать Tkinter, но у меня много проблем с настройкой графического интерфейса, я настроил игру, и в ней можно играть в текстовом режиме, но это не пройдет. Я провел немало исследований, но не могу понять, если кто-нибудь сможет мне помочь с этим, я с удовольствием это оценил бы. Мой код ниже.

from random import randint

def game():
#Board Setup-------------
hit = 0
ocean = []

for o in range (0, 10):
    ocean.append(["O"] * 10)

def print_ocean(ocean):
    for a in ocean:
        print (" ".join(a))

print_ocean(ocean)

#Ship placement----------

def random_row(ocean):
    return randint(0, len(ocean) - 1)

def random_col(ocean):
    return randint(0, len(ocean[0]) - 1)

a_row = random_row(ocean)
a_col = random_col(ocean)


b_row = random_row(ocean)
b_col = random_col(ocean)


c_row = random_row(ocean)
c_col = random_col(ocean)


d_row = random_row(ocean)
d_col = random_col(ocean)


e_row = random_row(ocean)
e_col = random_col(ocean)


#Ship Check--------------

def b_check():
      if b_row == a_row and b_col == a_col:
            b_row = random_row(ocean)
            b_col = random_col(ocean)
            return b_row
            return b_col
            b_check()

def c_check():
      if c_row == a_row and c_col == a_col or c_row == b_row and c_col == b_col:
            c_row = random_row(ocean)
            c_col = random_col(ocean)
            return c_row
            return c_col
            c_check()

def d_check():
      if d_row == a_row and d_col == a_col or d_row == b_row and d_col == b_col\
         or d_row == c_row and d_col == c_col:
            d_row = random_row(ocean)
            d_col = random_col(ocean)
            return d_row
            return d_col
            d_check()

def e_check():
      if e_row == a_row and e_col == a_col or e_row == b_row and e_col == b_col\
         or e_row == c_row and e_col == c_col or e_row == d_row and e_col == d_col:
            e_row = random_row(ocean)
            e_col = random_col(ocean)
            return e_row
            return e_col
            e_check()

#Restart-----------------

def restart():
    again = input("Captain would you like to start another attack? (Y/N)")
    if again == "y" or again == "Y":
        print ("Heading back into battle!")
        game()
    elif again == "n" or again == "N":
        print ("Retreating...")
        exit()
    else:
        print ("Captain, I don't understand that order (Y/N)")
        restart()

#Turn Setup--------------

for t in range(30):
    print ("")
    print ("Captain, ready to fire shell", t+1)
    print ("")
    guess_row = int(input("Captain, X coordiante: "))
    print("")
    guess_col = int(input("Captain, Y coordinate: "))
    print("")
    if (guess_row == a_row and guess_col == a_col) or (guess_row == b_row and guess_col == b_col)or\     
       (guess_row == c_row and guess_col == c_col) or (guess_row == d_row and guess_col == d_col)or\ 
       (guess_row == e_row and guess_col == e_col):
        ocean[guess_row][guess_col] = "S"
        print ("")
        print ("Captain, we sunk their battleship!")
        print ("")
        hit +=1
    elif guess_row not in range(10) or guess_col not in range(10):
        print ("Captain thats miles off target")
    elif ocean[guess_row][guess_col] == "X":
        print ("Captain, we've already fired there")
    else:
        print ("Captain we missed")
        ocean[guess_row][guess_col] = "X"
    print_ocean(ocean)

    if t == 14:
        print ("Captain, we're out of shells")
        restart()

    if hit == 5:
        print ("Captain, we sunk all of their ships!")
        restart()

print_ocean(ocean)
game()