Посмотрите этот пример:
начиная с первого уровня открытой иерархии, определите уровень и лист или родительский элемент. Если ваш уровень клиента = 3 и родитель, он найден
with tbl as (
select '12' id, null parent_id, 'main customer' status from dual
union all
select '13' id, null parent_id, 'main customer' status from dual
union all
select '131' id, 13 parent_id, 'main customer' status from dual
union all
select '121' id, 12 parent_id, 'main customer' status from dual
union all
select '1211' id, 121 parent_id, 'main customer' status from dual
union all
select '1212' id, 121 parent_id, 'main customer' status from dual
union all
select '12111' id, 1211 parent_id, 'main customer' status from dual
union all
select '12121' id, 1212 parent_id, 'main customer' status from dual)
select * from
(select tbl.*, level lvl, connect_by_isleaf leaf
from tbl
start with tbl.parent_id is null
connect by prior id = parent_id) b
where b.lvl = 3
AND b.status = 'main customer'
AND b.leaf = 0
вывод:
1211 121 main customer 3 0
1212 121 main customer 3 0