Преобразование массива с помощью Application.Index()
Этот подход сначала назначает значения таблицы массиву и в конечном итоге преобразует тот же массив в требуемую структуру, используя расширенные возможности Application.Index()
. функция, таким образом, поддерживая названия продуктов.
Я не претендую на то, что это самый эффективный способ, но он ясно демонстрирует возможности цитируемой функции - ср Некоторые особенности функции Application.Index
Примечание: я предполагаю, что включены все данные за месяц, т.е. даже пустые значения.
Sub Table2PivotBase()
' Purpose: Transform Table to Pivot base
' Method: reorganize Datafield array of table using advanced features of Application.Index in [2]d)
' Note: sheet references use the worksheet's CodeName property here
'~~~~~~~~~~~~ [0] Reference to table (address) ~~~~~~
Const MONTHSCOUNT& = 12, COLUMNOFFSET& = 1 ' number of months, column offset January = 1 (i.e. 2nd col)
With Sheet1
'a) Refer to table using the sheet's CodeName
Dim rpt As ListObject
Set rpt = .ListObjects("Table1")
Sheet1.CodeName
' ~~~~~~~~~~~ [1] Get Data ~~~~~~~~~~~~~~~~~~~~~~~~
'b) Assign table values in Sheet1 to 2-dim 1-based array
Dim arr As Variant, yr&
arr = .Range(rpt.Range.Address).Value2
'c) Extract current year from 1st month column in header (1+ coloffset 1 => 2nd column)
yr = Val(Split(arr(1, 1 + COLUMNOFFSET) & "-", "-")(1))
End With
'~~~~~~~~~~~~~~ [2] Reorganize Data ~~~~~~~~~~~~~~~
'd) Redimension array preserving 1st column
Dim arr2, ItemsCount&
ItemsCount = UBound(arr) - IIf(rpt.ShowTotals, 1, 0) ' exclude table totals from items count
arr2 = Application.Index(arr, Application.Transpose(getRowsArr(ItemsCount, MONTHSCOUNT)), Array(1, 1, 1, 2))
'e) Redefine headers in 1st row
Dim no&, headers
headers = Array("Product", "Year", "Month", "Data")
For no = 1 To 4
arr2(1, no) = headers(no - 1) ' headers are zerobased
Next no
'f) Enter year, month & month data in a loop
Const START& = 2
Dim i&, mon&, ii&
ii = START - 1
For i = START To UBound(arr2)
mon = (i - START) Mod MONTHSCOUNT + 1 ' 0 to 11 (omitting 1 caption row) + 1
If mon = 1 Then ii = ii + 1 ' increment data row of arr1 in January
'arr2(i, 1) has already been prefilled by section [2]d)
arr2(i, 2) = yr
arr2(i, 3) = Application.Text(DateSerial(yr, mon, 1), "mmm")
arr2(i, 4) = arr(ii, mon + COLUMNOFFSET)
Next i
'~~~~~~~~~~~~ ~[3] Write back pivot base to any sheet (via CodeName) ~~~~~~~~~~~
With Sheet2
.Range("A:D") = vbNullString
.Range("A1").Resize(UBound(arr2), UBound(arr2, 2)) = arr2
End With
End Sub
Вспомогательная функция getRowsArr()
Function getRowsArr(ByVal ItemsCount, Optional ByVal n& = 12) As Variant()
' Purpose: return 1-dim 0-based array containing n row numbers per item + title row no 1
' Note: allows restructuring the original array to contain all months data
Const START& = 2 ' data rang starts in 2nd row
Dim tmp(), i&, ii&
ReDim tmp(0 To (ItemsCount - 1) * n) ' includes header row number 1 at tmp(0) - zerobound!
'1) fill temporary array
tmp(0) = 1 ' title row no equals 1
For i = START To ItemsCount ' row no 2 to ...
For ii = 0 To n - 1 ' repeat row number n times
tmp((i - START) * n + ii + 1) = i
Next ii
Next i
'2) return Array(1,2,2,2,2,2,2,2,2,2,2,2,2,3,........3,4...,...) as function value
getRowsArr = tmp
'Debug.Print Left$(Join(tmp, ","), 65) & "..."
End Function