SELECT Name,'1','2','3'
FROM (
SELECT
database_jobdefect.defect_id,
database_session.name,
count(*) AS cu
FROM
database_session IN ner
JOIN database_job ON database_job.session_id = database_session.id
INNER JOIN database_jobdefect ON database_job.id = database_jobdefect.job_id
GROUP BY
database_session.name,
database_jobdefect.defect_id) PIVOT (count(database_session.name)
FOR database_jobdefect.defect_id IN ([1],[2],[3]))
Ошибка, которую я получаю:
"ProgrammingError: синтаксическая ошибка в или около" ("LINE 1: ... on.name, database_jobdefect.defect_id) PIVOT (count ( база данных _... "