У меня есть следующие фреймы данных
df1 <- data.frame(
Description=c("How are you- doing?", "will do it tomorrow otherwise: next week", "I will work hard to complete it for nextr week1 or tomorrow", "I am HAPPY with this situation now","Utilising this approach can helpα'x-ray", "We need to use interseting <U+0452> books to solve the issue", "Not sure if we could do it appropriately.", "The schools and Universities are closed in f -blook for a week", "Things are hectic here and we are busy"))
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и я хочу получить следующую таблицу:
d <- data.frame(
Description=c("Utilising this approach can helpa'x-ray", "How are you- doing", " We need to use interseting <U+0452> books to solve the issue ", " will do it tomorrow otherwise: next week ", " Things are hectic here and we are busy ", "I will work hard to complete it for nextr week1 or tomorrow ", "The schools and Universities are closed in f -blook for a week", " I am HAPPY with this situation now "," I will work hard to complete it for nextr week1 or tomorrow"))
f2<- read.table(text="B12 B6 B9
No Yes Yes
12 6 9
No No Yes
No No Yes
No No Yes
Yes No Yes
11 No Yes
12 11 P
No No Yes
", header=TRUE)
df3<-cbind(d,f2)
Как видно из столбца «Описание», есть пробел и двоеточие, и поэтому 1 после недели - это индекс, и я не смог это исправить. Я хочу сопоставить его на основе "Описание". Поэтому я хочу сопоставить df1 с df2, используя Description. Можем ли мы сделать это в R для этого случая?