Не распаковывает нужные данные из двоичного файла с Python - PullRequest
0 голосов
/ 23 марта 2020
headerlen = 2 + int(data[1])
ADC_wave = data[headerlen:-1]
ADC_wave = np.array(unpack('%sh' % int((len(ADC_wave) / 2)), ADC_wave))

Файл данных выглядит следующим образом: Возвращаемое количество: 1024 байта

'#42500\D7\f\D7\07\D6\EF\D6\EB\D7\f\D7*\D7\05\D6\9B\D6;\D6;\D6\9A\
D7\04\D7)\D7\0E\D6\ED\D6\EE\D7\02\D7\0B\D7\02\D6\F8\D6\FA\D7\00\
D7\02\D6\FF\D6\FD\D6\FE\D6\FF\D6\FF\D6\FF\D6\FF\D6\FF\D6\FF\D6\
FE\D6\FE\D6\FF\D7\00\D6\FF\D6\FC\D6\FD\D7\02\D7\03\D6\FD\D6\F7\
D6\FD\D7\t\D7\t\D6\F5\D6\E4\D6\FC\D7H\D7\AD\D7\FF\D8&\D8\s\D7\F4\
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D8\r\D7\F0\D7\FE\D8"\D8\0B\D7\A0\D77\D77\D7\A0\D8\n\D8"\D8\00\D7\
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D6\FF\D7\02\D6\FF\D6\FE\D7\01\D7\00\D6\FA\D6\F8\D7\04\D7\0E\D7\
00\D6\E3\D6\E9\D7=\D7\C3\D8#\D8\1A\D7\BA\D7I\D6\FC\D6\D8\D6\D7\
D7\b\D7f\D7\BB\D7\BE\D7f\D6\FD\D6\D2\D6\ED\D7\15\D7\15\D6\F6\D6\
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DC\D6\EE\D7G\D7\BF\D8\0F\D8\15\D7\F8\D7\F2\D8\0E\D8\13\D7\CB\D7F\
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F4\D6\ED\D78\D7\BA\D8\14\D8\18\D7\F6\D7\F3\D8\12\D8\0F\D7\C0\D7F\
D6\EF\D6\DF\D6\FA\D7\0F\D7\n\D6\F9\D6\F3\D6\FD\D7\b\D7\b\D6\FA\
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E2\FD\E2\B8\E2O'

Значение двоичных данных представляет собой шаг сигнала, но я получил случайное значение после запуска этого кода. Что означает 3-я строка кода? и почему я не могу получить правильный вывод.

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