Могу ли я создать представление с помощью запроса соединения в SQLALchemy

Question

Существуют ли возможности для создания представлений путем объединения двух таблиц в алхимии:

class CreateView(Executable, ClauseElement):
    def __init__(self, name, select):
        self.name = name
        self.select = select


@compiles(CreateView)
def visit_create_view(element, compiler, **kw):
    return "CREATE VIEW %s AS %s" % (
         element.name,
         compiler.process(element.select, literal_binds=True)
         )


# Method to create view with top three articles
def view_top_three():
    top_three_view = CreateView('test', db.select([art.columns.title, func.count(log.columns.path)]) 
        .group_by(policies.columns.name, join_object.columns.policy_name) \

    # engine.execute(top_three_view)

    v = Table('popular', metadata, autoload=True, autoload_with=engine)
    for r in engine.execute(v.select()):
        print(r)


def main():

    try:
        engine = db.create_engine(DATABASE_URI).execution_options(autocommit=True)
        connection = engine.connect()
    except:
        print('Error establishing DB connection')

    # Import metadata
    metadata = db.MetaData()

    # Import articles, authors and log tables
    art = db.Table('policies', metadata, autoload=True, autoload_with=engine)
    aut = db.Table('join_object', metadata, autoload=True, autoload_with=engine)

    # Call the method which creates view and selects from view
    view_top_three()