Я хочу запустить свой python скрипт как сервис, но каждый раз, когда я пытаюсь его выполнить, выдается системный выход 1 - PullRequest
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Я хочу запустить свой python скрипт как сервис, но каждый раз, когда я пытаюсь его выполнить, выдается системный выход 1

0 голосов
/ 31 января 2020

Вот мой код: 

import socket
import win32serviceutil
import win32service
import logging
import psutil
import configparser
import pyodbc
import time, threading
import win32event



logging.basicConfig(filename="ProcessMonitor.log", level=logging.INFO)
logging.info("Configured the logger")

config = configparser.ConfigParser()
config.sections()
config.read('ProcessMonitor.ini')
_host = config['ConnectionString']['host']
_user = config['ConnectionString']['user']
_password = config['ConnectionString']['passwd']
_database = config['ConnectionString']['db']
_processList = config['ProcessList']['process']

conn = pyodbc.connect(
    'DRIVER={SQL Server};SERVER=' + _host + ';DATABASE=' + _database + ';UID=' + _user + ';PWD=' + _password)
cursor = conn.cursor()

StartTime = time.time()


class setInterval:
    def __init__(self, interval, action):
        self.interval = interval
        self.action = action
        self.stopEvent = threading.Event()
        thread = threading.Thread(target=self.__setInterval)
        thread.start()

    def __setInterval(self):
        nextTime = time.time() + self.interval
        while not self.stopEvent.wait(nextTime - time.time()):
            nextTime += self.interval
            self.action()


def checkIfProcessRunning(processName):
    for proc in psutil.process_iter():
        try:
            if processName.lower() in proc.name().lower():
                return True
        except (psutil.NoSuchProcess, psutil.AccessDenied, psutil.ZombieProcess):
            pass
    logging.exception('Process Not running ')
    return False;


def insertProcessintoDB(runningStatus, applicationIndex):
    try:
        if runningStatus == 0:
            sql_query = "UPDATE DB.dbo.SysMonitor Set StatusCode = 4, StatusMsg='FAILURE', LastTimestamp = " \
                        "GETUTCDATE()  where ApplicationIndex =" + str(applicationIndex)
        elif runningStatus == 1:
            sql_query = "UPDATE DB.dbo.SysMonitor Set StatusCode = 1 , StatusMsg = 'OK', LastTimestamp = " \
                        "GETUTCDATE() where ApplicationIndex =" + str(applicationIndex)
        cursor.execute(sql_query)
        conn.commit()
    except Exception as e:
        logging.exception('Insertion Error' + str(e))


def checkProcessStatus(pname, appIndex):
    isrunning = 0
    if checkIfProcessRunning(pname):
        print(pname + ' is running')
        isrunning = 1
    else:
        print('Alert! ' + pname + ' is not running')
        insertProcessintoDB(isrunning, appIndex)


def main():
    print("*** Checking if process is running ***")
    processes = _processList.split(';')
    for _process_ in processes:
        _processInfo_ = _process_.split(',')
        processName = _processInfo_[0]
        applicationIndex = _processInfo_[1]
        checkProcessStatus(processName, applicationIndex)


def runmain():
    inter = setInterval(30, main)


class Service(win32serviceutil.ServiceFramework):
    _svc_name_ = "ProcessMonitor"
    _svc_display_name_ = "ProcessMonitor"
    _svc_description_ = " Python service to check running status for processes"

    @classmethod
    def parse_command_line(cls):

        win32serviceutil.HandleCommandLine(cls)

    def __init__(self, *args):
        win32serviceutil.ServiceFramework.__init__(self, args)
        self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
        socket.setdefaulttimeout(60)
       #win32serviceutil.ServiceFramework.__init__(*args)
        #elf.process = Process(target=self.runmain)

    def SvcStop(self):
        logging.shutdown()
        self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
        self.process.terminate()
        self.ReportServiceStatus(win32service.SERVICE_STOPPED)

    def SvcDoRun(self):
        self.process.start()
        Service.LogMsg(Service.EVENTLOG_INFORMATION_TYPE,
                              Service.PYS_SERVICE_STARTED,
                              (self._svc_name_, ' '))
        self.process.run()

if __name__ == '__main__':
    Service.parse_command_line()

Когда я пытаюсь выполнить код, я вижу Файл "C: \ Users \ a \ Anaconda3 \ lib \ site-packages \ win32 \ lib \ win32serviceutil.py ", строка 523, используется sys.exit (1). Как мне go решить эту проблему? Я не вижу никаких файлов DLL тоже. Я следил за https://www.thepythoncorner.com/2018/08/how-to-create-a-windows-service-in-python/.

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