Как сделать общий класс для десериализации Gson

Question

Имея json,

{
  "owner": {
  "name": "frank",
  "address": "some street",
  "city": "a city"
  },
  "employees": [
    {
      "name": "todd",
      "address": "some street2",
      "city": "a city2",
      "title": "manager"
    },
    {
      "name": "micheal",
      "address": "some street3",
      "city": "a city3",
      "title": "engineer"
    }
  ],
  "partner": {
    "name": "ford",
    "address": "some street a",
    "city": "Magdeburg",
    "employees": [
      {
        "name": "marina",
        "address": "some street2",
        "city": "a city2",
        "title": "sectary"
      }
    ]
  }
}

с помощью инструмента POJO, чтобы получить модель данных для десериализации в классы, и посмотрите, как минимум,

"name", "address", "city"

распространены в json objects.

вопрос: как сделать общее выражение Person (val name: String, val address: String, val city: String) для использования в модели данных для десериализации Gson?

@ApiSerializable
@Parcelize
data class Owner(
  @SerializedName("name")
  val name: String? = null,
  @SerializedName("address")
  val address: String? = null,
  @SerializedName("city")
  val city: String? = null
) : Parcelable

@ApiSerializable
@Parcelize
data class Employee(
  @SerializedName("name")
  val name: String? = null,
  @SerializedName("address")
  val address: String? = null,
  @SerializedName("city")
  val city: String? = null,
  @SerializedName("title")
  val title: String? = null

) : Parcelable

@ApiSerializable
@Parcelize
data class employees(
  @SerializedName("employees")
  val employees: List<Employee>? = null
) : Parcelable

@ApiSerializable
@Parcelize
data class Partner(
  @SerializedName("name")
  val name: String? = null,
  @SerializedName("address")
  val address: String? = null,
  @SerializedName("city")
  val city: String? = null,
  @SerializedName("employees")
  val employees: List<Employee>? = null
) : Parcelable