from os import environ
from datetime import datetime
from sqlalchemy import (Boolean, Column, ForeignKey, Integer, String,
create_engine, Float, DateTime, Table)
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import relationship, sessionmaker
Base = declarative_base()
# Many to Many
association_favorite = Table('Team_favorite', Base.Metada,
Column('Favorite_user_id', Integer,
ForeignKey('UserData.id')),
Column('Favorite_team_id', Integer,
ForeignKey('TeamSchedule.id'))
)
# Many to Many
association_job = Table('Tob_today', Base.Metada,
Column('Today_user_id', Integer,
ForeignKey('UserData.id')),
Column('Today_team_id', Integer,
ForeignKey('TeamSchedule.id'))
)
# Table user
class UserData(Base):
__tablename__ = 'user_data'
id = Column(Integer, primary_key=True)
username = Column(String)
user_id = Column(Integer)
team = relationship('TeamSchedule', secondary=association_favorite,
backref='data_user')
job_everyday = relationship('job_day', secondary=association_job,
backref='data_job')
# Table Iteam favorite user
class TeamSchedule(Base):
__tablename__ = 'champion_league_try'
id = Column(Integer,
primary_key=True, nullable=False)
columns_1 = Column(String)
columns_2 = Column(DateTime)
# engine use pyscopg2
engine = create_engine(environ['DATABASE_URL'])
Session = sessionmaker(bind=engine)
Base.metadata.create_all(engine)
Можно ли создать many to many
таким образом?
Я хочу создать таблицу отношений many to many
2.
Это мой синтаксис неправильный, чтобы создать его?
Я запутался в этой части. Для создания таблицы отношений многие ко многим снова. job_everyday = relationship('job_day', secondary=association_job,
backref='data_job')
Представление моего стола.
table 1
------------
table 2
-----------
table 3 many to many table 1 and table 2
-----------
table 4 many to many table 1 and table 2
-----------