когда я выполняю простой запрос в улье, например select * from table3 limit 100; , результат в порядке. но когда я выполняю select count (*) из table3; , я сталкиваюсь со следующей ошибкой:
0: hiv> select count(*) from table3;
INFO : Compiling command(queryId=hive_20200329113344_1afc6405-bf94-4c96-a7a3-50d97a45f7bb): select count(*) from table3
INFO : Semantic Analysis Completed (retrial = false)
INFO : Returning Hive schema: Schema(fieldSchemas:[FieldSchema(name:_c0, type:bigint, comment:null)], properties:null)
INFO : Completed compiling command(queryId=hive_20200329113344_1afc6405-bf94-4c96-a7a3-50d97a45f7bb); Time taken: 0.24 seconds
INFO : Executing command(queryId=hive_20200329113344_1afc6405-bf94-4c96-a7a3-50d97a45f7bb): select count(*) from table3
INFO : Query ID = hive_20200329113344_1afc6405-bf94-4c96-a7a3-50d97a45f7bb
INFO : Total jobs = 1
INFO : Launching Job 1 out of 1
INFO : Starting task [Stage-1:MAPRED] in serial mode
WARN : The session: sessionId=d229f221-9c07-449b-bf8d-651c6392bb70, queueName=null, user=hive, doAs=true, isOpen=false, isDefault=false has not been opened
INFO : Subscribed to counters: [] for queryId: hive_20200329113344_1afc6405-bf94-4c96-a7a3-50d97a45f7bb
INFO : Tez session hasn't been created yet. Opening session
ERROR : Failed to execute tez graph.
org.apache.tez.dag.api.TezException: org.apache.hadoop.yarn.exceptions.YarnException: Failed to submit application_1582632679991_0006 to YARN : org.apache.hadoop.security.AccessControlException: Queue root.default already has 1 applications, cannot accept submission of application: application_1582632679991_0006
at org.apache.tez.client.TezClient.start(TezClient.java:407) ~[tez-api-0.9.1.3.0.1.0-187.jar:0.9.1.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.tez.TezSessionState.startSessionAndContainers(TezSessionState.java:516) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.tez.TezSessionState.openInternal(TezSessionState.java:451) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.tez.TezSessionPoolSession.openInternal(TezSessionPoolSession.java:124) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.tez.TezSessionState.open(TezSessionState.java:373) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.tez.TezTask.ensureSessionHasResources(TezTask.java:372) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.tez.TezTask.execute(TezTask.java:199) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.Task.executeTask(Task.java:210) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.exec.TaskRunner.runSequential(TaskRunner.java:97) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.Driver.launchTask(Driver.java:2701) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.Driver.execute(Driver.java:2372) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.Driver.runInternal(Driver.java:2048) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:1746) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.Driver.run(Driver.java:1740) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hadoop.hive.ql.reexec.ReExecDriver.run(ReExecDriver.java:157) ~[hive-exec-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hive.service.cli.operation.SQLOperation.runQuery(SQLOperation.java:226) ~[hive-service-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hive.service.cli.operation.SQLOperation.access$700(SQLOperation.java:87) ~[hive-service-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at org.apache.hive.service.cli.operation.SQLOperation$BackgroundWork$1.run(SQLOperation.java:318) ~[hive-service-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at java.security.AccessController.doPrivileged(Native Method) ~[?:1.8.0_171]
at javax.security.auth.Subject.doAs(Subject.java:422) ~[?:1.8.0_171]
at org.apache.hadoop.security.UserGroupInformation.doAs(UserGroupInformation.java:1730) ~[hadoop-common-3.1.1.3.0.1.0-187.jar:?]
at org.apache.hive.service.cli.operation.SQLOperation$BackgroundWork.run(SQLOperation.java:331) ~[hive-service-3.1.0.3.0.1.0-187.jar:3.1.0.3.0.1.0-187]
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) ~[?:1.8.0_171]
at java.util.concurrent.FutureTask.run(FutureTask.java:266) ~[?:1.8.0_171]
at java.util.concurrent.Executors$RunnableAdapter.call(Executors.java:511) ~[?:1.8.0_171]
at java.util.concurrent.FutureTask.run(FutureTask.java:266) ~[?:1.8.0_171]
at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1149) ~[?:1.8.0_171]
at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:624) ~[?:1.8.0_171]
at java.lang.Thread.run(Thread.java:748) [?:1.8.0_171]
Caused by: org.apache.hadoop.yarn.exceptions.YarnException: Failed to submit application_1582632679991_0006 to YARN : org.apache.hadoop.security.AccessControlException: Queue root.default already has 1 applications, cannot accept submission of application: application_1582632679991_0006
at org.apache.hadoop.yarn.client.api.impl.YarnClientImpl.submitApplication(YarnClientImpl.java:304) ~[hadoop-yarn-client-3.1.1.3.0.1.0-187.jar:?]
at org.apache.tez.client.TezYarnClient.submitApplication(TezYarnClient.java:77) ~[tez-api-0.9.1.3.0.1.0-187.jar:0.9.1.3.0.1.0-187]
at org.apache.tez.client.TezClient.start(TezClient.java:402) ~[tez-api-0.9.1.3.0.1.0-187.jar:0.9.1.3.0.1.0-187]
... 28 more
ERROR : FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.exec.tez.TezTask
INFO : Completed executing command(queryId=hive_20200329113344_1afc6405-bf94-4c96-a7a3-50d97a45f7bb); Time taken: 0.422 seconds
Error: Error while processing statement: FAILED: Execution Error, return code 1 from org.apache.hadoop.hive.ql.exec.tez.TezTask (state=08S01,code=1)
, и это ошибка, которую я вижу в приложениях пряжи ResourceManager UI >> для этого приложения
org.apache.hadoop.security.AccessControlException: Queue root.default already has 1 applications, cannot accept submission of application: application_1582632679991_0006